C#.net http |如何从API获取对象层

"Newtonsoft.Json.JsonSerializationException: 'Cannot deserialize the current JSON array (e.g. [1,2,3]) into type 'Dashboard.Weather' because the type requires a JSON object (e.g. {"name":"value"}) to deserialize correctly."

感谢您的帮助,我正在努力天气.描述“,下面是我的示例代码:

public class Weather
{
    public string Description{ get; set; }
}

public class Product
{
    public Weather Weather { get; set; }
}

public static class ApiHelper
{
    static string city_id = "CITY_ID";
    static string api_key = "API_KEY";
    public static HttpClient client = new HttpClient();

    public static void InitializeClient()
    {
        client.BaseAddress = new Uri($"http://api.openweathermap.org/data/2.5/weather?id={city_id}&APPID={api_key}");
        client.DefaultRequestHeaders.Accept.Clear();
        client.DefaultRequestHeaders.Accept.Add(
            new MediaTypeWithQualityHeaderValue("application/json"));
    }

    public static async Task<Weather> GetProductAsync()
    {
        Product product = null;
        HttpResponseMessage response = await client.GetAsync("");
        if (response.IsSuccessStatusCode)
        {
            product = await response.Content.ReadAsAsync<Product>();
        }
        return product.Weather;

    }
}

    async void SetLabelText()
    {
        var weather = await ApiHelper.GetProductAsync();

        descriptionLabel.Text = $"Description: {weather.Description}";
    }

API的响应格式如下

{"coord":{"lon":-89.59,"lat":41.56},"weather":[{"id":800,"main":"Clear","description":"clear sky","icon":"01d"}],"base":"stations","main":{"temp":279.27,"feels_like":275.4,"temp_min":278.15,"temp_max":280.37,"pressure":1027,"humidity":74},"visibility":16093,"wind":{"speed":3.1,"deg":200},"clouds":{"all":1},"dt":1576951484,"sys":{"type":1,"id":3561,"country":"US","sunrise":1576934493,"sunset":1576967469},"timezone":-21600,"id":4915397,"name":"Walnut","cod":200}