Umbraco ModelsBuilder-如何从子节点获取强类型对象

IEnumerable<YourModel> childrenOfType = model.Children<YourModel>();

YourModel Where() Cast<T>()

List<ACommonType> IPublishedContent

foreach(IPublishedContent c in collectionOfIPublishedContent)
{
    // basic if
    if (c.DocumentTypeAlias == YourModel.ModelTypeAlias)
    {
        YourModel stronglyTypedContent = c as YourModel;
        // do some stuff
    }

    // or switch...
    switch (c.DocumentTypeAlias)
    {
        case YourModel.ModelTypeAlias:
            YourModel stronglyTypedContent2 = c as YourModel;
            // do a thing
            break;
    }

    // or use implicit casts with null checking
    YourModel stronglyTypedContent3 = c as YourModel;
    if (stronglyTypedContent3 != null)
    {
        // congrats, your content is of the type YourModel
    }
}

var components = model.Children
    .Where(x => x.DocumentTypeAlias == PageComponentsFolder.ModelTypeAlias)
    .Single().Children; 

foreach (var component in components)
{    
    string componentNodeTypeAlias = component.DocumentTypeAlias;

    switch (componentNodeTypeAlias)
    {
        case SimpleHero.ModelTypeAlias:
            Html.Partial("component_simpleHero", component as SimpleHero)
            break;

        case VideoWithHtml.ModelTypeAlias:
            Html.Partial("component_videoWithHTML", component as VideoWithHtml)
            break;
    }
}