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Angular http.get()返回带有数据的数组

httpclient angular

0

Amber Akkermans · 技术社区 · 1 年前

我有一项服务:

import { Injectable } from '@angular/core';
import { Observable } from 'rxjs';
import { Color } from '../model/color';
import { HttpClient } from '@angular/common/http';

@Injectable({
  providedIn: 'root'
})
export class ColorService {
  private productsUrl = 'http://localhost:5500/colors/';

  constructor(private http: HttpClient) { }

  getColors(): Observable<Color[]> {
    var colors = this.http.get<Color[]>(this.productsUrl + "all");
    
    return colors;
  }
}

以及获得该方法的结果的组件:

ngOnInit(): void {
    this.colorsService.getColors()
        .subscribe((colors) => {
          this.colors = Object.values(colors);
          this.colors.sort((a,b) => a.name.localeCompare(b.name));
          console.log(colors);
        }, err => {
          this.displaySpinner = false;
        }, () => {
          this.displaySpinner = false;
        });
  }

我的Color界面如下所示:

export interface Color {
    id: number;
    number: string;
    name: string;
    imagePath: string;
    category: string;
    color: string;
    brand: string;
}

现在,当我在组件中执行此控制台日志时,它会给我一个名为colors的数组,并将另一个具有实际数据的数组作为子数组:

{
  colors: [
    {
      id: 1,
      number: 159,
      name: 'glamorous peach',
      imagePath: '/src/assets/img/colors/color104.jpeg',
      category: 'summer',
      color: 'orange',
      brand: 'Pink Gellac'
    }
  ]
}

我似乎记得以前版本的angular不是这样的,当我在html页面中做下面这样的事情时,它无法获得color.name,我想是因为这里发生了数组嵌套:

<mat-grid-tile *ngFor="let color of colors">
            <mat-card class="example-card"
                style="width: 95%; border-radius:15px; box-shadow: 4px 4px 6px -1px rgba(0,0,0,0.15);">
                <mat-card-content>
                    <mat-grid-list cols="1" rowHeight="250">
                        <mat-grid-tile class="tile" style="overflow:auto;">
                          <div class="wrapper">
                            <p>{{color.name}}</p>
                          </div>
                        </mat-grid-tile>
                      </mat-grid-list>
                </mat-card-content>
            </mat-card>
        </mat-grid-tile>

你知道如何解决这个问题吗?由于在服务中键入(Color[]),我似乎无法将此数组操作为ngFor工作所需的值。。

3 回复 | 直到 1 年前

1

Naren Murali 1 年前

该结构来自API,您只需要对其进行不同的设置即可使其工作!访问颜色数组并将其设置为变量!

ngOnInit(): void {
    this.colorsService.getColors()
        .subscribe((response: any) => {
          console.log(response);
          this.colors = <Array<Color>>response.colors;
          this.colors.sort((a,b) => a.name.localeCompare(b.name));
        }, err => {
          this.displaySpinner = false;
        }, () => {
          this.displaySpinner = false;
        });
  }

2

1

Kareem Adel 1 年前

在将颜色数组分配给this.colors之前,可以修改组件代码以从响应中提取颜色数组。

ngOnInit(): void {
  this.colorsService.getColors()
    .subscribe((response) => {
      // Extract the colors array from the response
      const colorsArray = response.colors;

      // Sort and assign the colors array to this.colors
      this.colors = colorsArray.sort((a, b) => a.name.localeCompare(b.name));

      console.log(this.colors);
    }, err => {
      this.displaySpinner = false;
    }, () => {
      this.displaySpinner = false;
    });
}

<!--  HTML template, you can iterate over this.colors directly: -->
<mat-grid-tile *ngFor="let color of colors">
  <mat-card class="example-card" style="width: 95%; border-radius:15px; box-shadow: 4px 4px 6px -1px rgba(0,0,0,0.15);">
    <mat-card-content>
      <mat-grid-list cols="1" rowHeight="250">
        <mat-grid-tile class="tile" style="overflow:auto;">
          <div class="wrapper">
            <p>{{color.name}}</p>
          </div>
        </mat-grid-tile>
      </mat-grid-list>
    </mat-card-content>
  </mat-card>
</mat-grid-tile>

3

0

Yong Shun 1 年前

或者,您可以转换Observable值以检索 colors 阵列通过 map RxJS operator .

import { map, Observable } from 'rxjs';


@Injectable({
  providedIn: 'root',
})
export class ColorService {
  ...

  getColors(): Observable<Color[]> {
    return this.http
      .get<any>(this.productsUrl + 'all')
      .pipe(map((resp: any) => resp.colors as Color[]));
  }
}

Demo @ StackBlitz