什么是zip(函数式编程?)

zipWith (+) [1, 2, 3] [4, 5, 6]

输出:

[5, 7, 9]

zip

输入:

zip [1, 2, 3] [4, 5, 6]

输出:

[(1, 4), (2, 5), (3, 6)]

zip xs ys = zipWith (\x y -> (xs, ys)) xs ys 

例如,假设你有一个带(1,2,3)的列表,另一个带“一”、“二”、“三”的列表

scala> List(1,2,3).zip(List("one","two","three"))
res2: List[(Int, java.lang.String)] = List((1,one), (2,two), (3,three))

zip xs ys = zipWith xs ys (\x y -> (xs, ys))

是

zip xs ys = zipWith (\x y -> (x,y)) xs ys

zip = zipWith (\x y -> (x,y))

你可以在Python中使用以下代码:

>>> a = [1,2]
>>> b = [3,4]
>>> zip(a,b)
[(1,3),(2,4)]

let x = [1;2]
let y = ["hello"; "world"]
let z = Seq.zip x y

价值 z

[(1, "hello"); (2, "world")]