用重叠窗口计算RMS

我有一个一维的浮点数组 root mean square 值,每个值使用相同的窗口长度计算。比方说

RMS = {0, 0.01, 0.4, ... }

RMS[i] RMS[i + len] . 在这里 len

我想创建一个滚动窗口。我想要

rollingRMS[0] = RMS from 0 to len
...
rollingRMS[n] = RMS from n to len+n

尽可能有效地计算。我知道这并不难破解,但有人准备好了代码吗?

编辑: 终止 在每个元素上。

// The RMS data to be analysed
float[] RMS = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
// The resulting rolling RMS values
float[] rollingRMS = new float[RMS.Length];
// Window lenght
int len = 3;
// Calculate: rollingRMS will hold root mean square from windows which end at 
// each respective sample in the RMS array. For the first len samples the input
// will be treated as zero-padded
for (int i = 0; i < RMS.Length; i++)
{
    if (i == 0)
        rollingRMS[i] = (float)Math.Sqrt((RMS[i] * RMS[i] / len));
    else if (i < len)
        rollingRMS[i] = (float)Math.Sqrt(
            (   RMS[i] * RMS[i] + 
                len * (rollingRMS[i - 1] * rollingRMS[i - 1])
            ) / len);
    else
        rollingRMS[i] = (float)Math.Sqrt(
            (   len * (rollingRMS[i - 1] * rollingRMS[i - 1]) +
                RMS[i] * RMS[i] -
                RMS[i - len] * RMS[i - len]
            ) / len);
}