代码之家 › 专栏 › 技术社区 › dnndeveloper

统一解决多个类

strategy-pattern unity-container c#

dnndeveloper · 技术社区 · 14 年前

如何让microsoft unity为给定的接口类型“构造”类列表。

非常简单的例子:

  List<IShippingCalculation> list = new List<IShippingCalculation>();
  list.Add(new NewYorkShippingCalculation());
  list.Add(new FloridaShippingCalculation());
  list.Add(new AlaskShippingCalculation());

  //Not What I want
  public void calcship(List<IShippingCalculation> list)
  {
    var info = new ShippingInfo(list);
    info.CalculateShippingAmount(State.Alaska)
  }

  //Somehow in unity, must i do this for all the concrete classes? 
  //how does it know to give a list.
  Container.RegisterType<IShippingInfo,new AlaskaShippingCalculation()>();??

  //What I want
  public void calcship(IShippingInfo info)
  {
    info.CalculateShippingAmount(State.Alaska)
  }

谢谢你!

2 回复 | 直到 13 年前

Stephan 14 年前

如果你使用Unity 2,你可以使用 ResolveAll<T>

Container.RegisterType<IShippingInfo,FloridaShippingCalculation>("Florida");
Container.RegisterType<IShippingInfo,NewYorkShippingCalculation>("NewYork");
Container.RegisterType<IShippingInfo,AlaskaShippingCalculation>("Alaska");

IEnumerable<IShippingInfo> infos = Container.ResolveAll<IShippingInfo>();

您必须为每个注册指定一个名称,因为ResolveAll只返回命名注册。