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序列化哈希数组

ruby

1

craig · 技术社区 · 7 年前

  records = [
    {
      ID: 'BOATY',
      Name: 'McBoatface, Boaty'
    },
    {
      ID: 'TRAINY',
      Name: 'McTrainface, Trainy'
    }
  ]

我试图将它们组合成一个字符串数组:

["ID,BOATY","Name,McBoatface, Boaty","ID,TRAINY","Name,McTrainface, Trainy"]

irb> records.collect{|r| r.each{|k,v| "\"#{k},#{v}\"" }}
#=> [{:ID=>"BOATY", :Name=>"McBoatface, Boaty"}, {:ID=>"TRAINY", :Name=>"McTrainface, Trainy"}]

格式化(即。 ["Key0,Value0","Key1,Value1",...] 需要匹配供应商的接口。

**/编辑**

我错过了什么?

4 回复 | 直到 7 年前

1

3

Andrey Deineko 7 年前

records.flat_map(&:to_a).map { |a| a.join(',') }
#=> ["ID,BOATY", "Name,McBoatface, Boaty", "ID,TRAINY", "Name,McTrainface, Trainy"]

2

Thomas 7 年前

records = [
  {
    ID: 'BOATY',
    Name: 'McBoatface, Boaty'
  },
  {
    ID: 'TRAINY',
    Name: 'McTrainface, Trainy'
  }
]


# strait forward code
result= []
records.each do |hash|
  hash.each do |key, value|
    result<< key.to_s
    result<< value
  end
end
puts result.inspect

# a rubyish way (probably less efficient, I've not done the benchmark)
puts records.map(&:to_a).flatten.map(&:to_s).inspect

3

1

Arihant 7 年前

li = []
records.each do |rec|
    rec.each do |k,v|
      li << "#{k.to_s},#{v.to_s}".to_s
    end
end

print li

[“ID,BOATY”,“Name,McBoatface,BOATY”,“ID,TRAINY”,“Name,McTrainface,

4

0

Nondv 7 年前

你确定要这样做吗?

退房 Marshal . 或者 JSON

你甚至可以用这种愚蠢的方式 Hash#inspect eval :

serialized_hashes = records.map(&:inspect) # ["{ID: 'Boaty'...", ...]
unserialized = serialized_hashes.map { |s| eval(s) }