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如何从命令行忽略或处理django劫持?

  •  0
  • Keith John Hutchison  · 技术社区  · 8 年前

    当我使用从命令行运行测试时

      ./manage.py test
    

    Traceback (most recent call last):
      File "./manage.py", line 10, in <module>
        execute_from_command_line(sys.argv)
      File "/usr/local/lib/python2.7/site-packages/django/core/management/__init__.py", line 367, in execute_from_command_line
        utility.execute()
      File "/usr/local/lib/python2.7/site-packages/django/core/management/__init__.py", line 341, in execute
        django.setup()
      File "/usr/local/lib/python2.7/site-packages/django/__init__.py", line 27, in setup
        apps.populate(settings.INSTALLED_APPS)
      File "/usr/local/lib/python2.7/site-packages/django/apps/registry.py", line 85, in populate
        app_config = AppConfig.create(entry)
      File "/usr/local/lib/python2.7/site-packages/django/apps/config.py", line 90, in create
        module = import_module(entry)
      File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/importlib/__init__.py", line 37, in import_module
        __import__(name)
    ImportError: No module named hijack
    

    现在hijack实际上已经安装好了,因为我可以在运行服务器时从浏览器中使用它

    ./manage.py runserver
    

    管理的内容。py是

    #!/usr/bin/env python
    import os
    import sys
    
    if __name__ == "__main__":
        os.environ.setdefault("DJANGO_SETTINGS_MODULE", "mtmdjango.settings")
    
        from django.core.management import execute_from_command_line
    
        execute_from_command_line(sys.argv)
    

    (有人能创建并添加标签django jackit吗)

    1 回复  |  直到 8 年前
        1
  •  0
  •   Keith John Hutchison    8 年前

    我在

    https://docs.djangoproject.com/en/1.10/intro/tutorial01/ https://docs.djangoproject.com/en/1.10/intro/tutorial05/

    结果是我的命令行错了。

    python manage.py test contacts
    

    给我我期望的输出。