使用criteriabuilder和entitymanager时无法获取一组对象

当我试图使用CriteriaBuilder和entityManager从一个名为SeedRecord的实体中获取一组属性时,出现以下错误:

org.hibernate.hql.internal.ast.querysyntaxception:找不到 类上的适当构造函数 [DTO.EntityDTO.AffiliatelinksPersedSummaryDTO]。预期参数 分别是:long、java.lang.String、java.lang.String、POJOs.AffiliateLink [选择新的 DTOs.EntityDTOs.affiliatelinkspersedsummarydto(generatedAlias0.id, generatedAlias0.varietyName、generatedAlias0.produceName, generatedAlias1)从POJOs.SeedRecord作为generatedAlias0内部连接 generatedAlias0.附属链接为generatedAlias1]

根据stacktrace,包装类的affiliatelinkspersedsummarydto应该有一个构造函数,该构造函数包含一个类型为 Pojo.AffiliateLink . 但实际字段是对一组附属链接的引用,而不是对单个附属链接行的引用,因此这没有任何意义。有人能告诉我这是什么原因吗?下面是包装类的代码:

public class AffiliateLinksPerSeedSummaryDTO {
    private long id;
    private String varietyName;
    private String produceName;
    @JsonIgnore
    private Set<AffiliateLink> affiliateLinks;
    private long specificCount;
    private long generalCount;

    public AffiliateLinksPerSeedSummaryDTO(long id, String varietyName, String produceName, Set<AffiliateLink> affiliateLinks) {
        this.id = id;
        this.varietyName = varietyName;
        this.produceName = produceName;
        this.affiliateLinks = affiliateLinks;
    }

所有字段名与SeedRecord字段名完全相同。

这是我用来获取所需字段/对象的代码片段。

    EntityManager em = seedRecordDao.getEntityManager();
    CriteriaBuilder builder = em.getCriteriaBuilder();
    CriteriaQuery<AffiliateLinksPerSeedSummaryDTO> criteria = builder.createQuery(AffiliateLinksPerSeedSummaryDTO.class);
    Root<SeedRecord> seedRecordRoot = criteria.from(SeedRecord.class);
    criteria.select(
            builder.construct(
                    AffiliateLinksPerSeedSummaryDTO.class,
                    seedRecordRoot.get("id"),
                    seedRecordRoot.get("varietyName"),
                    seedRecordRoot.get("produceName"),
                    seedRecordRoot.join("affiliateLinks")));

    List<AffiliateLinksPerSeedSummaryDTO> affiliateLinksPerSeed = em.createQuery(criteria).getResultList();

编辑:我最近的一次尝试是通过检索元组而不是使用包装器对象。现在的问题是,尽管数据库中有值,resultlist还是为零。这就是我现在做的:

    public Set<AffiliateLinksPerSeedSummaryDTO> getAffiliateLinksPerSeed(){
        EntityManager em = seedRecordDao.getEntityManager();
        CriteriaBuilder builder = em.getCriteriaBuilder();
        Metamodel m = em.getMetamodel();
        EntityType<SeedRecord> SeedRecord_ = m.entity(SeedRecord.class);
        CriteriaQuery<Tuple> criteria = builder.createTupleQuery();
        Root<SeedRecord> seedRecordRoot = criteria.from(SeedRecord.class);
        Path<Long> idPath = seedRecordRoot.get( "id" );
        Path<String> varietyNamePath = seedRecordRoot.get("varietyName");
        Path<String> produceNamePath = seedRecordRoot.get("produceName");
        Join<SeedRecord,AffiliateLink> affiliateLinks = seedRecordRoot.join("affiliateLinks");
        criteria.multiselect(idPath,varietyNamePath,produceNamePath);

//        criteria.select(
//                builder.construct(
//                        AffiliateLinksPerSeedSummaryDTO.class,
//                        seedRecordRoot.get("id"),
//                        seedRecordRoot.get("varietyName"),
//                        seedRecordRoot.get("produceName"),
//                        seedRecordRoot.get(SeedRecord_.getSet("affiliateLinks",AffiliateLink.class))));

        List<Tuple> affiliateLinksPerSeed = em.createQuery(criteria).getResultList();
        log.info("the count is: " + affiliateLinksPerSeed.size());
                //seedRecordDao.getAffiliateLinksPerSeed();
        return affiliateLinksPerSeed.stream().map(tuple ->{
            Map<Boolean, Long> collect = ((List<AffiliateLink>)tuple.get(affiliateLinks)).stream()
                    .collect(Collectors.partitioningBy(AffiliateLink::isGeneral, Collectors.counting()));
            return new AffiliateLinksPerSeedSummaryDTO(((Long)tuple.get(idPath)), ((String)tuple.get(varietyNamePath)), ((String)tuple.get(produceNamePath)),collect.get(true), collect.get(false));
        }).collect(Collectors.toSet());
    }