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.NET中的性能和foreach循环

foreach performance

Jagd Dai · 技术社区 · 15 年前

我有以下单击事件。

protected void btnUpdate_Click(object sender, EventArgs e) {
        foreach (GridViewRow gvr in gvEditBulletins.Rows) {
            RadEditor re = (RadEditor)gvr.FindControl("reBulletin");
            DropDownList ddl = (DropDownList)gvr.FindControl("ddlPosition");

            // Business logic
        }
    }

在每次迭代中声明一个radeditor和dropdownlist的实例后,我是否会受到性能上的影响,或者编译器是否足够聪明,能够知道如何重用这些实例?

4 回复 | 直到 15 年前

jason 15 年前

首先,即使担心这是一个微优化;在研究应用程序的性能之前,您不应该担心这一点,分析表明此方法和此循环是瓶颈。其次,是的,编译器将重用本地变量的同一个实例 re 和 ddl .

下面是一个非常简单的例子:

class Program {
    static void Main(string[] args) {
        string[] strings = new [] { "hello", "world" };
        foreach (string s in strings) {
            int i = s.Length;
        }
        return;
    }
}

这里是IL:

.method private hidebysig static void Main(string[] args) cil managed {
    .entrypoint
    .maxstack 3
    .locals init (
        [0] string[] strings,
        [1] string s,
--->    [2] int32 i,
        [3] string[] CS$0$0000,
        [4] string[] CS$6$0001,
        [5] int32 CS$7$0002,
        [6] bool CS$4$0003)
    L_0000: nop 
    L_0001: ldc.i4.2 
    L_0002: newarr string
    L_0007: stloc.3 
    L_0008: ldloc.3 
    L_0009: ldc.i4.0 
    L_000a: ldstr "hello"
    L_000f: stelem.ref 
    L_0010: ldloc.3 
    L_0011: ldc.i4.1 
    L_0012: ldstr "world"
    L_0017: stelem.ref 
    L_0018: ldloc.3 
    L_0019: stloc.0 
    L_001a: nop 
    L_001b: ldloc.0 
    L_001c: stloc.s CS$6$0001
    L_001e: ldc.i4.0 
    L_001f: stloc.s CS$7$0002
    L_0021: br.s L_0038
    L_0023: ldloc.s CS$6$0001
    L_0025: ldloc.s CS$7$0002
    L_0027: ldelem.ref 
    L_0028: stloc.1 
    L_0029: nop 
    L_002a: ldloc.1 
--->L_002b: callvirt instance int32 [mscorlib]System.String::get_Length()
--->L_0030: stloc.2
    L_0031: nop 
    L_0032: ldloc.s CS$7$0002
    L_0034: ldc.i4.1 
    L_0035: add 
    L_0036: stloc.s CS$7$0002
    L_0038: ldloc.s CS$7$0002
    L_003a: ldloc.s CS$6$0001
    L_003c: ldlen 
    L_003d: conv.i4 
    L_003e: clt 
    L_0040: stloc.s CS$4$0003
    L_0042: ldloc.s CS$4$0003
    L_0044: brtrue.s L_0023
    L_0046: br.s L_0048
    L_0048: ret