PostgreSQL:将间隔格式化为分钟

SELECT EXTRACT(EPOCH FROM '2 months 3 days 12 hours 65 minutes'::INTERVAL)/60;

似乎有用。

警告:“似乎”是关键词。

正如前面的答案所指出的,诀窍是将间隔转换为“epoch”,即秒的绝对数,然后适当地除以其他单位的绝对数。

几年前,我写过 an interval_convert function date_part ,假设一个月是30天,一年是365.25天。

您可以随意使用和修改:

CREATE FUNCTION 
    interval_convert(in_unit text, in_interval interval) 
    RETURNS double precision
AS $FUNC$
    SELECT
        EXTRACT(
            EPOCH FROM
            $2 -- in_interval 
        )
        /
        -- Slightly lazy way of allowing both singular and plural
        --  has side effect that 'centurie' and 'centurys' are accepted
        --  but otherwise behaves similarly to DATE_TRUNC
        CASE TRIM(TRAILING 's' FROM LOWER(
            $1 -- in_unit
        ))
            WHEN 'microsecond'  THEN 0.000001 
            WHEN 'millisecond'  THEN 0.001
            WHEN 'second'       THEN 1
            WHEN 'minute'       THEN 60
            WHEN 'hour'         THEN 3600
            WHEN 'day'          THEN 86400
            WHEN 'week'         THEN 604800
            WHEN 'month'        THEN 2592000 -- 30 days
            -- WHEN 'quarter'      THEN -- Not supported
            WHEN 'year'         THEN 31557600 -- 365.35 days
            WHEN 'decade'       THEN 315576000
            WHEN 'century'      THEN 3155760000
            WHEN 'centurie'     THEN 3155760000
            WHEN 'millennium'   THEN 31557600000
            WHEN 'millennia'    THEN 31557600000
        END
$FUNC$
    LANGUAGE sql 
    IMMUTABLE 
    RETURNS NULL ON NULL INPUT;

postgres=# select date_part('minutes', '65 minutes'::interval);
 date_part 
-----------
         5
(1 row)

postgres=# select '65 minutes'::interval
postgres-# ;
 interval 
----------
 01:05:00
(1 row)