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在bash脚本中添加JSON元素

http shell bash json

1

Josh · 技术社区 · 7 年前

在我的bash脚本中,有一行代码如下所示:

JOB_RESULTS=$(curl --fail -k -H "Content-Type: application/xml" --write-out HTTP_CODE='%{http_code}' "${request_url}")

该行输出以下内容:

{"name":"callCLF010Job","id":11693,"status":"STARTING","message":"The job has started.","exitCode":"exitCode=UNKNOWN;exitDescription="}HTTP_CODE=200

HTTP_CODE 输入JSON消息。

有没有办法让回报看起来像 {"name":"callCLF010Job","id":11693,"status":"STARTING","message":"The job has started.","exitCode":"exitCode=UNKNOWN;exitDescription=","HTTP_CODE":"200"}

编辑:

http_code="${JOB_RESULTS:${#JOB_RESULTS}-17}"
http_body="${JOB_RESULTS:0:${#JOB_RESULTS}-17}"
http_code_json=", ${http_code}}"
my_result="${http_body/%\}/$http_code_json}"

echo $my_result 我的输出如下所示:

{"name":"callCLF010Job","id":11702,"status":"STARTING","message":"The job has started.","exitCode":"exitCode=UNKNOWN;exitDescriptio

2 回复 | 直到 7 年前

1

Murilo 7 年前

一种方法是使用sed以您想要的方式格式化输出:

echo $JOB_RESULTS | sed 's/}HTTP_CODE=\([0-9]\+\)$/,"HTTP_CODE":"\1"}/'

或者在你的命令里:

JOB_RESULTS=$(curl --fail -k -H "Content-Type: application/xml" --write-out HTTP_CODE='%{http_code}' "${request_url}" | sed 's/}HTTP_CODE=\([0-9]\+\)$/,"HTTP_CODE":"\1"}/')

2

1

confetti 7 年前

这是使用 shell parameter expansion 完成任务。(除此之外,纯粹的恶作剧 curl

curlout=$(curl -s --fail -k -H "Content-Type: application/xml" --write-out '"HTTP_CODE":"%{http_code}"' "http://example.com")
http_code="${curlout:${#curlout}-17}"
http_body="${curlout:0:${#curlout}-17}"
http_code_json=", ${http_code}}"
my_result="${http_body/%\}/$http_code_json}"

替换 http://example.com

为了防止错误URL或(no)输出时出错,应该将最后四行放在 if-construct if [[ $http_code != '"HTTP_CODE":"000"' ]]