masm x86中的冒泡排序在几个交互之后没有排序

因此,我尝试使用以下代码作为模板来实现BubbleSort:

    int n = arr.length;  
    int temp = 0;  
     for(int i=0; i < n; i++){  
             for(int j=1; j < (n-i); j++){  
                      if(arr[j-1] > arr[j]){  
                             //swap elements  
                             temp = arr[j-1];  
                             arr[j-1] = arr[j];  
                             arr[j] = temp;  

但是,我的汇编代码只对前1-2次进行排序,并产生错误的结果。我试过多次运行调试器,但我天真的眼睛看不到翻译中的任何错误。

.data
arr DWORD 3,2,1,4,5
temp DWORD 0
arr_j DWORD 0
; Bubble Sort
.code
main proc
mov esi, OFFSET arr
mov eax, 0 ; for outer loop
mov ebx, 1 ; for inner loop

OuterLoop:

     InnerLoop:

        ; swap elements
        ; referencing j in array
        call MULTIPLY
        add edx, esi ; edx = esi + 4*ebx that is *arr[j]
        mov edi, [edx]
        mov [arr_j], edi ; store arr[j]
        sub edx, 4
        mov edi, [edx] ; store arr[j - 1]

        cmp edi, [arr_j] ; if(arr[j-1] > arr[j]) -> swap elements
        jle FAIL_SWAP

        ; swap elements here
        mov [temp], edi
        mov edi, [arr_j]
        mov ebp, [temp]
        mov [edx], edi ; arr[j - 1] < arr[j]
        add edx, 4
        mov [edx], ebp

        FAIL_SWAP:

     inc ebx
     mov ecx, LENGTHOF arr
     sub ecx, eax
     cmp ebx, ecx
     jl InnerLoop

inc eax
cmp eax, LENGTHOF arr
jl OuterLoop     


invoke ExitProcess,0
main ENDP

MULTIPLY PROC ; multiply 4 with ebx, store at edx
    push esi

    xor esi, esi
    mov esi, 1

    mov edx, ebx

    LOOPER:
    add edx, ebx

    inc esi
    cmp esi, 4
    jl LOOPER

    pop esi
    ret
MULTIPLY ENDP
END main

任何帮助都非常感谢。谢谢。