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序列化程序返回对象字段

django-serializer django-views django-rest-framework django-models django

Franco · 技术社区 · 6 年前

我接收的是DRF输出的模型对象,而不是实际的字段。

我想接收音频链接和发布艺术家表的所有项目。

这是我有的。

输出

{ "title": "Attack The Dancefloor Volume Two", "audiolinks": [ "AudioLinks object (55708)", "AudioLinks object (55709)", "AudioLinks object (55710)", "AudioLinks object (55711)" ], "releaseartists": [ "ReleaseArtists object (140)", "ReleaseArtists object (141)" ] }

型号.py

class AudioLinks(models.Model):
    release = models.ForeignKey('ReleasesAll', models.DO_NOTHING, db_column='release_id', related_name='audiolinks')
    track_number = models.IntegerField()
    class Meta:
        managed = False
        db_table = 'audio_links'

class ReleaseArtists(models.Model):
    release = models.ForeignKey('ReleasesAll', models.DO_NOTHING, db_column='release_id', related_name='releaseartists')
    artists = models.CharField(max_length=100)

    class Meta:
        managed = False
        db_table = 'release_artists'

视图.py

class ListReleaseDetailView(generics.RetrieveUpdateDestroyAPIView):

    queryset = ReleasesAll.objects.all()
    serializer_class = ReleasesSerializer
    def get(self, request, *args, **kwargs):
        try:
            a_release = self.queryset.prefetch_related('releaseartists','audiolinks').get(pk=kwargs['release_id'])
            return Response(ReleasesSerializer(a_release).data)

        except ReleasesAll.DoesNotExist:
            return Response(
                data = {
                    "message": "{} does not exist".format(kwargs["release_id"])
                },
                status=status.HTTP_404_NOT_FOUND
            )

序列化程序.py

class ReleasesSerializer(serializers.ModelSerializer):
    audiolinks = serializers.StringRelatedField(many=True)
    releaseartists = serializers.StringRelatedField(many=True)

    class Meta:
        model = ReleasesAll
        fields = ('title','audiolinks','releaseartists')

1 回复 | 直到 6 年前

Sreekanth Reddy Balne 6 年前

serializers.stringRelatedField 给出 __str__ 在模型上定义的方法。

AudioLinks object (55708) “还有 ReleaseArtists object (141) __str公司__ 任何模型的表示。

class AudioLinksSerializer(serializers.ModelSerializer):
    class Meta:
        model = AudioLinks
        fields = ('__all__')

class ReleaseArtistsSerializer(serializers.ModelSerializer):
    audiolinks = serializers.StringRelatedField(many=True)
    releaseartists = serializers.StringRelatedField(many=True)

    class Meta:
        model = ReleaseArtists
        fields = ('__all__')

然后:

class ReleasesSerializer(serializers.ModelSerializer):
    audiolinks = AudioLinksSerializer(many=True)
    releaseartists = ReleaseArtistsSerializer(many=True)

    class Meta:
        model = ReleasesAll
        fields = ('title','audiolinks','releaseartists')

这足以让你得到所有的领域。

***同样按照Django惯例,你需要用单数形式命名模型,即, AudioLink , ReleaseArtist audiolinks 你可能会想“有很多AudioLink对象,而我得到的却很少”