如何将字符串转换成复杂的<浮点> C++?

只需添加括号和默认值 operator>> 将为您提供:

#include <iostream>
#include <string>
#include <complex>
#include <sstream>
int main()
{
        std::string s = "123,5.3";//input

        std::istringstream is('(' + s + ')');
        std::complex<float> c;
        is >> c;

        std::cout << "the number is " << c << "\n";
}

有趣的是,每个人的风格都略有不同,尽管答案是一样的。

    std::complex<float> c = boost::lexical_cast<std::complex<float> >('('+s+')');

The complex class has an extraction operator.