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如何将正数和负数分开到各自的列中?

sybase sql

19

Mike Sickler · 技术社区 · 16 年前

我有一个包含以下列和数据的表:

activity_dt | activity_amt
 2009-01-01 |   -500
 2009-01-01 |    750

我可以写一个查询来查看 activity_amt

activity_dt | debits | credits
 2009-01-01 |  -500  |   750

4 回复 | 直到 10 年前

1

38

Floern themue 10 年前

select activity_dt, 
    sum(case when activity_amt < 0 then activity_amt else 0 end) as debits, 
    sum(case when activity_amt > 0 then activity_amt else 0 end) as credits
from the_table
group by activity_dt
order by activity_dt

2

5

Guffa 16 年前

我不确定Sybase中的确切语法,但您应该能够对日期进行分组,并总结正负值:

select
  activity_dt,
  sum(case when activity_amt < 0 then activity_amt else 0 end) as debits,
  sum(case when activity_amt >= 0 then activity_amt else 0 end) as credits
from
  theTable
group by
  activity_dt

3

0

eggyal 13 年前

我使用 DECODE 我希望这对每个人都有用。

select activity_dt, 
sum((DECODE(activity_amt /-ABS(activity_amt), 1, activity_amt, 0))) as credits,
sum((DECODE(activity_amt /-ABS(activity_amt), -1, activity_amt, 0))) as debits
from the_table
group by activity_dt
order by activity_dt;

4

0

Igor Borisenko 11 年前

select (select JV_GroupsHead.GroupTitle
         from JV_GroupsHead
         whereJV_GroupsHead.Id=jv.GroupId) as 'GroupName'
        ,jv.Revenue
        ,jv.AccountNo
        ,jv.AccountNoTitle
        ,(case when jv.Revenue  < 0 then jv.Revenue  else 0 end) as 'debits'
        ,(case when jv.Revenue> 0 then jv.Revenue  else 0 end) as 'credits'
from JVFunction1('2010-07-08','2010-08-08') as jv