代码之家 › 专栏 › 技术社区 › Razvan Zamfir

在Codeigniter 3中上载时,如何显示不允许的文件类型错误?

codeigniter-3 validation

Razvan Zamfir · 技术社区 · 6 年前

我正在做一个基本的工作 blog application 具有和 引导4 .

当然,这些帖子都有主要的图片。有一个 默认图像 如果用户没有上传图像,但是上传了,有 只允许3种类型

帖子控制器:

// Upload image
$config['upload_path'] = './assets/img/posts';
$config['allowed_types'] = 'jpg|jpeg|png';
$config['max_size'] = '2048';

$this->load->library('upload', $config);

if(!$this->upload->do_upload()){

    $data['uerrors'] = $this->upload->display_errors();

    if ($data['uerrors']) {
        $this->load->view('partials/header', $data);
        $this->load->view('dashboard/create-post');
        $this->load->view('partials/footer');
    } else {
        $post_image = 'default.jpg';
    }

} else {
    $data = array('upload_data' => $this->upload->data());
    $post_image = $_FILES['userfile']['name'];
}

<?php foreach ($uerrors as $uerror): ?>
  <span><?php echo $uerror; ?></span>
<?php endforeach; ?>

然而,我得到了一个错误。

这是整个 create()

public function create() {

    // Only logged in users can create posts
    if (!$this->session->userdata('is_logged_in')) {
        redirect('login');
    }

    $data = $this->get_data();
    $data['tagline'] = "Add New Post";

    if ($data['categories']) {
        foreach ($data['categories'] as &$category) {
            $category->posts_count = $this->Posts_model->count_posts_in_category($category->id);
        }
    }

    $this->form_validation->set_rules('title', 'Title', 'required');
    $this->form_validation->set_rules('desc', 'Short description', 'required');
    $this->form_validation->set_rules('body', 'Body', 'required');
    $this->form_validation->set_error_delimiters('<p class="error-message">', '</p>');

    if($this->form_validation->run() === FALSE){
        $this->load->view('partials/header', $data);
        $this->load->view('dashboard/create-post');
        $this->load->view('partials/footer');
    } else {
        // Create slug (from title)
        $slug = url_title(convert_accented_characters($this->input->post('title')), 'dash', TRUE);
        $slugcount = $this->Posts_model->slug_count($slug, null);
        if ($slugcount > 0) {
            $slug = $slug."-".$slugcount;
        }

        // Upload image
        $config['upload_path'] = './assets/img/posts';
        $config['allowed_types'] = 'jpg|jpeg|png';
        $config['max_size'] = '2048';

        $this->load->library('upload', $config);

        if(!$this->upload->do_upload()){

            $data['uerrors'] = $this->upload->display_errors();

            if ($data['uerrors']) {
                $this->load->view('partials/header', $data);
                $this->load->view('dashboard/create-post');
                $this->load->view('partials/footer');
            } else {
                $post_image = 'default.jpg';
            }

        } else {
            $data = array('upload_data' => $this->upload->data());
            $post_image = $_FILES['userfile']['name'];
        }

        $this->Posts_model->create_post($post_image, $slug);
        $this->session->set_flashdata('post_created', 'Your post has been created');
        redirect('/');
    }
}

我的错在哪里?

0 回复 | 直到 6 年前

ubayedtanvir 6 年前

你的上传代码看起来不错,但你需要更新以下更改。

'dashboard/create-post' 当您传递给您的 'partials/header' 查看。你的 '仪表板/创建帖子' 视图没有得到任何上传错误消息,所以它说 'Undefined variable: uerrors'

if(!$this->upload->do_upload()){
    $data['uerrors'] = $this->upload->display_errors();
    if ($data['uerrors']) {
        $this->load->view('partials/header', $data);
        $this->load->view('dashboard/create-post', $data);
        $this->load->view('partials/footer');
    } else {
        $post_image = 'default.jpg';
    }
} else {
    $post_image = $this->upload->data('file_name');
}

作为 CodeIgniter Documentation 如果说,'display\u errors()'返回字符串,而不是数组,则不必遍历错误。在你的脸上回音就行了 '仪表板/创建帖子'

private function uploadFile(){
    if ($_FILES['userfile']['name'] === '') {
        return array(
            'status' => TRUE,
            'message' => 'No file selected.',
            'file_name' => 'default.jpg'
        );
    }

    // Upload image
    $config['upload_path'] = './assets/img/posts';
    $config['allowed_types'] = 'jpg|jpeg|png';
    $config['max_size'] = '2048';

    $this->load->library('upload', $config);

    if(!$this->upload->do_upload('userfile')){
        return array(
            'status' => FALSE,
            'message' => $this->upload->display_errors('<p class="text-danger ">', '</p>'),
            'file_name' => ''
        );
    }else{
        return array(
            'status' => TRUE,
            'message' => 'File uploaded successfully',
            'file_name' => $this->upload->data('file_name')
        );
    }
}

那么整个create方法应该如下所示-

public function create() {
    // Only logged in users can create posts
    if (!$this->session->userdata('is_logged_in')) {
        redirect('login');
    }

    $data = $this->get_data();
    $data['tagline'] = "Add New Post";

    if ($data['categories']) {
        foreach ($data['categories'] as &$category) {
            $category->posts_count = $this->Posts_model->count_posts_in_category($category->id);
        }
    }

    $this->form_validation->set_rules('title', 'Title', 'required');
    $this->form_validation->set_rules('desc', 'Short description', 'required');
    $this->form_validation->set_rules('body', 'Body', 'required');
    $this->form_validation->set_error_delimiters('<p class="error-message">', '</p>');

    if($this->form_validation->run() === FALSE){
        $this->load->view('partials/header', $data);
        $this->load->view('dashboard/create-post');
        $this->load->view('partials/footer');
    } else {
        $upload = $this->uploadFile();

        if($upload['status'] === FALSE){
            $data['upload_error'] = $upload['message'];

            $this->load->view('partials/header', $data);
            $this->load->view('dashboard/create-post', $data);
            $this->load->view('partials/footer');
        }else{
            // Create slug (from title)
            $slug = url_title(convert_accented_characters($this->input->post('title')), 'dash', TRUE);
            $slugcount = $this->Posts_model->slug_count($slug, null);
            if ($slugcount > 0) {
                $slug = $slug."-".$slugcount;
            }

            $this->Posts_model->create_post($upload['file_name'], $slug);
            $this->session->set_flashdata('post_created', 'Your post has been created');
            redirect('/');
        }
    }
}

最后将这行代码添加到查看文件,就在文件输入按钮之后。

<?php if(isset($upload_error)) echo $upload_error; ?>

我认为一切都应该奏效。

Stephen Mudere 6 年前

我在这里学到了三样东西

1) 没有像前面提到的那样将$数据传递给正确的视图

在我看来

<form action="http://localhost:8000/welcome/create" method="post" enctype="multipart/form-data">
          <input type="file" name="lname" ><br>
          <input type="submit" value="Submit">
        </form>

if(!$this->upload->do_upload("lname")){

上载错误的文件类型以测试此错误。您可能需要额外的长度来检测实际上载文件的文件类型。

Razvan Zamfir 6 年前

如果通过修改 create() 这种方式:

public function create() {

    // Only logged in users can create posts
    if (!$this->session->userdata('is_logged_in')) {
        redirect('login');
    }

    $data = $this->get_data();
    $data['tagline'] = "Add New Post";

    if ($data['categories']) {
        foreach ($data['categories'] as &$category) {
            $category->posts_count = $this->Posts_model->count_posts_in_category($category->id);
        }
    }

    $this->form_validation->set_rules('title', 'Title', 'required');
    $this->form_validation->set_rules('desc', 'Short description', 'required');
    $this->form_validation->set_rules('body', 'Body', 'required');
    $this->form_validation->set_error_delimiters('<p class="error-message">', '</p>');

    if($this->form_validation->run() === FALSE){
        $this->load->view('partials/header', $data);
        $this->load->view('dashboard/create-post');
        $this->load->view('partials/footer');
    } else {
        // Create slug (from title)
        $slug = url_title(convert_accented_characters($this->input->post('title')), 'dash', TRUE);
        $slugcount = $this->Posts_model->slug_count($slug, null);
        if ($slugcount > 0) {
            $slug = $slug."-".$slugcount;
        }

        // Upload image
        $config['upload_path'] = './assets/img/posts';
        $config['allowed_types'] = 'jpg|jpeg|png';
        $config['max_size'] = '2048';

        $this->load->library('upload', $config);

        if(!$this->upload->do_upload()){

            $errors = array('error' => $this->upload->display_errors());

            // Display upload validation errors 
            // only if a file is uploaded and there are errors
            if (empty($_FILES['userfile']['name'])) {
                $errors = [];
            }

            if (empty($errors)) {
                $post_image = 'default.jpg';
            } else {
                $data['upload_errors'] = $errors;
            }

        } else {
            $data = array('upload_data' => $this->upload->data());
            $post_image = $_FILES['userfile']['name'];
        }

        if (empty($errors)) {
            $this->Posts_model->create_post($post_image, $slug);
            $this->session->set_flashdata('post_created', 'Your post has been created');
            redirect('/');
        } else {
            $this->load->view('partials/header', $data);
            $this->load->view('dashboard/create-post');
            $this->load->view('partials/footer');
        }
    }
}

create-post.php 我的看法是:

<?php if(isset($upload_errors)){
   foreach ($upload_errors as $upload_error) {
    echo $upload_error;
   }
 }?>

Lajos Arpad 6 年前

此错误告诉您变量不存在或未初始化。看看这个代码

$data['uerrors'] = $this->upload->display_errors();

if ($data['uerrors']) {

$uerrors 未初始化的某个变量(此代码中未显示)。注意,我不相信 array 指数 'uerrors' 数组

Hamza AVvan 6 年前

你的问题有点含糊。不管怎样,变量 $uerrors 什么时候能定下来 create() 方法将执行,我相信将在POST请求时执行。另外,你没有提到这是哪一部分:

<?php foreach ($uerrors as $uerror): ?>
  <span><?php echo $uerror; ?> </span>
<?php endforeach; ?>

如果是的话 dashboard/create-post 查看然后尝试通过 $data partials/header

我刚检查了密码点火器 View/Controller samples 我发现使用 isset() 函数调用,因此不要直接执行foreach循环,请执行以下操作:

<? if (isset($uerrors)): ?>
    <? foreach ($uerrors as $uerror): ?>
      <span><?= $uerror; ?></span>
    <? endforeach; ?> 
<? endif; ?>

Shehroz Altaf 6 年前

$data['uerrors'] = '';

或者检查前端的值是否不为空。

前端,您可以这样做:

<?php  if (isset($uerrors) && $uerrors != '') {
            foreach ($uerrors as $uerror) {
                echo '<span>' . $uerror . '</span>';
            }
        } ?>

您的控制器将是:

 $data = array();
        // Upload image
        $config['upload_path'] = './assets/img/posts';
        $config['allowed_types'] = 'jpg|jpeg|png';
        $config['max_size'] = '2048';

        $this->load->library('upload', $config);

        /*You need to initialize  $data['uerrors'] as null because you are using it on front end*/
        $data['uerrors'] = '';
        if (!$this->upload->do_upload('FilePath')) {
            $data['uerrors'] = $this->upload->display_errors();
            $this->load->view('partials/header', $data);
            $this->load->view('dashboard/create-post');
            $this->load->view('partials/footer');
        } else {
            if (isset($_POST{'your_file'})) {
                /*'check your images here that you are receiving from front end'*/
            } else {
                /*If there is no image, then default image is*/
                $post_image = 'default.jpg';
            }
            $data = array('upload_data' => $this->upload->data());
            $post_image = $_FILES['userfile']['name'];
        }

你可以在网上找到更多有用的帖子 How to upload image in CodeIgniter?