我有一个带有Customer\u ID、Customer\u Name、Address1、Address2、Mail\u Address1、Mail\u Address2等的表。
在某些情况下,Mail_Address1=“相同”或“。。。。这基本上意味着我需要提取Address1+Address2,否则忽略并获取Mail\u Address1+Mail\u Address2。
我的伪SQL查询如下所示:-
// The query that would give me all the records with the same address as Address1 for Mailing Address //
SELECT Customer_ID, Customer_Name, Address1 + ', ' + Address2 as Address, ....
FROM Customers
Where Customer_ID != 0 AND (Mail_Address1 ='Same' or Mail_Address1 ='')
SELECT Customer_ID, Customer_Name, Mail_Address1 + ', ' + Mail_Address2 as Address, ....
FROM Customers
Where Customer_ID != 0 AND Mail_Address1 !='Same' AND Mail_Address1 !=''