在Bash的文件路径参数中获取last dirname/filename

basename 删除路径的目录前缀:

$ basename /usr/local/svn/repos/example
example
$ echo "/server/root/$(basename /usr/local/svn/repos/example)"
/server/root/example

以下方法可用于获取路径名的任何路径:

some_path=a/b/c
echo $(basename $some_path)
echo $(basename $(dirname $some_path))
echo $(basename $(dirname $(dirname $some_path)))

输出:

c
b
a

basename

subdir="/path/to/whatever/${1##*/}"