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php foreach循环仅返回数组中第一次迭代的值

inner-join foreach arrays mysql php

Ben J · 技术社区 · 8 年前

据我所知,阵列正在正确循环,正如您可以看到的那样 当前结果 在这里: https://i.imgur.com/JWD3nis.png 但奇怪的是ID:2没有生成表,ID 5创建了2个表,根据刚刚链接的imgur屏幕截图,都是空白的。

我仔细检查了我的样本数据,每个表有5条唯一的记录,没有重复或问题。

编辑:1 我忘了提及期望的结果,以澄清我希望循环如何工作。请查看此屏幕截图: https://i.imgur.com/4h7l49p.png

编辑:2 https://pastebin.com/MG2gtASu 这是我的如果有帮助: https://i.imgur.com/idVR5ev.png

编辑:3 新的更新代码(谢谢Sand):

<?php
include('OrderCore/connect-db.php');
$POIds = array();
if ($result = $mysqli->query("SELECT ProductionOrderID FROM ProductionOrder" ) ) {
    while ($row = $result->fetch_object()) {
        $POIds[] = $row->ProductionOrderID;
    }
}
foreach ( $POIds as $index => $OrderId ) {
    if ( $result = $mysqli->query("
    SELECT * 
    FROM ProductionOrder AS p
    LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderStatusID ) 
    LEFT JOIN NotGood AS n ON ( p.ProductionOrderID = n.NGID ) 
    LEFT JOIN BatchOrder AS b ON ( p.ProductionOrderID = b.BatchID ) 
    LEFT JOIN Brand AS bd ON ( p.ProductionOrderID = bd.BrandID ) 
    LEFT JOIN CustomerOrder AS co ON ( p.ProductionOrderID = co.COID ) 
    LEFT JOIN Customer AS c ON ( p.ProductionOrderID = c.CustomerID ) 
    LEFT JOIN CustomerOrderStatus AS cos ON ( p.ProductionOrderID = cos.COStatusID ) 
    WHERE p.ProductionOrderID='$OrderId'") ) {
        while( $row = $result->fetch_object() ) {
            print "<h1>Order: $OrderId</h1>";
            print "<table class='table table-striped'>";
            print "<tr> <th>PO ID</th> <th>PO #</th> <th>Order Quantity</th> <th>Balance Left</th> <th>Production Date</th> <th>Production Order Status</th> <th>Not Good ID</th> </tr>";
            print "<td>" . $row->ProductionOrderID . "</td>";
            print "<td>" . $row->PONum . "</td>";
            print "<td>" . $row->OrderQTY . "</td>";
            print "<td>" . $row->BalLeftNum . "</td>";
            print "<td>" . $row->ProductionDate . "</td>";
            print "<td>" . $row->ProductionOrderStatusID . "</td>";
            print "<td>" . $row->NGID . "</td>";
            print "</tr>";
            print "</table>";
            //BatchOrder
            print "<table class='table table-striped'>";
            print "<tr> <th>Batch ID</th> <th>Brand Name</th> <th>Batch Quantity</th> <th>Availability Date</th> <th>Remaining Balance</th> <th>Production Order ID</th> </tr>";
            print "<td>" . $row->BatchID . "</td>";
            print "<td>" . $row->BrandID . "</td>";
            print "<td>" . $row->BatchQTY . "</td>";
            print "<td>" . $row->AvailDate . "</td>";
            print "<td>" . $row->RemainBal . "</td>";
            print "<td>" . $row->ProductionOrderID . "</td>";
            print "</tr>";
            print "</table>";
            //CustomerOrder
            print "<table class='table table-striped'>";
            print "<tr> <th>Customer ID</th> <th>Customer Name</th> <th>Invoice Quantity</th> <th>Invoice #</th> <th>Shipping Date</th> <th>Batch ID</th> <th>CO Status</th> </tr>";
            print "<td>" . $row->COID . "</td>";
            print "<td>" . $row->CustomerID . "</td>";
            print "<td>" . $row->InvoiceQTY . "</td>";
            print "<td>" . $row->InvoiceNum . "</td>";
            print "<td>" . $row->ShipDate . "</td>";
            print "<td>" . $row->BatchID . "</td>";
            print "<td>" . $row->COStatusID . "</td>";
            print "</tr>";
            print "</table>";
        }
    }
    else
    {
        print "No results to display!";
    }
}
$mysqli->close();
?>

2 回复 | 直到 8 年前

S4NDM4N 8 年前

我知道为什么会这样,这是因为连接类型 INNER this

发现了为什么只显示一批数据的问题。因为你在扳平比分 p.ProductionOrderID = b.BatchID 所以,查询会将生产ID与批次ID匹配,并且批次ID是唯一的,所以不会出现重复项,从而显示匹配行中的单个数据记录。您真正想要做的是匹配批次表中的生产ID,因为这是生产表和批次表之间的关系。现在,当您运行此操作时,它将绘制表格,直到批处理结束。

while 或 foreach 你不需要另一个 SQL $row["BatchQTY"]

这是我的解决方案。

if ( $result = $mysqli->query("
    SELECT * 
FROM ProductionOrder AS p
LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderStatusID ) 
LEFT JOIN NotGood AS n ON ( p.ProductionOrderID = n.NGID ) 
LEFT JOIN BatchOrder AS b ON ( p.ProductionOrderID = b.ProductionOrderID)//Changed this equation 
LEFT JOIN Brand AS bd ON ( p.ProductionOrderID = bd.BrandID ) 
LEFT JOIN CustomerOrder AS co ON ( p.ProductionOrderID = co.COID ) 
LEFT JOIN Customer AS c ON ( p.ProductionOrderID = c.CustomerID ) 
LEFT JOIN CustomerOrderStatus AS cos ON ( p.ProductionOrderID = cos.COStatusID )
    WHERE p.ProductionOrderID='$OrderId'")

Shahriar63 8 年前

在while循环内键入

echo "<pre>";
print_r($row);
echo "</pre>";

选择查询 .