尝试在子查询中使用“node.name AS name”,即。
SELECT node.name, (COUNT(parent.name) - (sub_tree.depth + 1)) AS depth
FROM line_items AS node,
line_items AS parent,
line_items AS sub_parent,
(SELECT node.name AS name, (COUNT(parent.name) - 1) AS depth
FROM line_items AS node,
line_items AS parent
WHERE node.lft BETWEEN parent.lft AND parent.rgt
AND node.name = 'Power Up'
GROUP BY node.name
ORDER BY node.lft
) AS sub_tree
WHERE node.lft BETWEEN parent.lft AND parent.rgt
AND node.lft BETWEEN sub_parent.lft AND sub_parent.rgt
AND sub_parent.name = sub_tree.name
GROUP BY node.name
HAVING depth <= 1
ORDER BY node.lft;
至少似乎消除了错误。