启动进程上虚假的“进程列表”输出

在ps1脚本中,我有以下内容:

Write-Host "MySqlDump Running"
$runProg = "C:/Program Files/MariaDB 10.4/bin/mysqldump.exe"
$runArgs = "JcTest --user=JcTest --password=JcTestPass --databases=TRUE --host=localhost --port=23246"
Start-Process -FilePath $runProg -ArgumentList $runArgs -RedirectStandardOutput "backup.sql" -Wait -PassThru -NoNewWindow
Write-Host "MySqlDump Finished"

backupFolder "C:\Backups" # A routine in a .psm1 module to create a 7Zip of a complete folder

执行时,控制台输出如下:

[C:\...\JCPrompt]> .\backupProj.ps1
MySqlDump Running

 NPM(K)    PM(M)      WS(M)     CPU(s)      Id  SI ProcessName
 ------    -----      -----     ------      --  -- -----------
      7     3.47       6.05       0.02   29524   1 mysqldump
MySqlDump Finished


7-Zip 19.00 (x64) : Copyright (c) 1999-2018 Igor Pavlov : 2019-02-21
      5     0.73       3.18       0.00   25332   1 7za
[C:\...\JcPrompt]> Scanning the drive:
367 folders, 1313 files, 92447874 bytes (89 MiB)

控制台输出中似乎混入了虚假的进程列表。还要注意7zip输出中间的PS提示。这在执行后立即出现 Start-Process 电话。

最后,此脚本还需要 <enter> 最终返回PS提示。

任何线索都将是最受欢迎的!

备份文件夹的来源:

[CmdletBinding()]
Param(
    [Parameter(Mandatory = $true, Position = 0)]
    [string]$folderName
)

Set-StrictMode -Version Latest

$folderCurrent = (Get-Location).Path + "\"

Set-Location $folderName
$folderBase = (Get-Location).Path + "\"
$folderName = $folderBase.Split("\" )[-2]

Do_dsBackup ($folderBase + "*.*") ( $pathBackups + "\" + $folderName + '-' + (Get-dsShortDate))

Set-Location $folderCurrent

----------

function Do_dsBackup ( [String]$7zipSrc, [String]$7zipDest)
{
    if (-not $7zipSrc.StartsWith('"')) { $7zipSrc = Get-dsQuoted( $7zipSrc) }
    if (-not $7zipDest.StartsWith('"')) { $7zipDest = Get-dsQuoted( $7zipDest) }

    Start-Process -Wait -NoNewWindow -RedirectStandardOutput=".\NUL" -FilePath "c:\4dos\7za.exe" -ArgumentList "a -r -y", $7zipDest, $7zipSrc
}