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CloudFoundry中的多个服务实例之间的Spring引导管理不能有所不同

spring-boot-admin

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Domo · 技术社区 · 7 年前

我让Spring Boot Admin在本地运行Eureka Service Discovery(客户机中不依赖于SBA)。现在我尝试在CloudFoundry中部署它。根据文档,版本2.0.1应该“支持CloudFoundry开箱即用”。

我的问题是,当我将一个服务扩展到多个实例时,它们都在同一主机名和端口下注册。Eureka向我显示了我配置的所有实例及其instanceID,如下所示:

eureka:
  instance:
    instanceId: ${spring.application.name}:${vcap.application.instance_id:${spring.application.instance_id:${random.value}}}

但是SpringBoot管理员只列出一个以hostname:port作为标识符的实例。我认为我必须在客户机上配置一些东西,以便它在注册时发送每个HTTP头的实例ID。但我不知道怎么做。

1 回复 | 直到 7 年前

1

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Domo 7 年前

显然,您必须在客户机的启动/contextrefresh时将CloudFoundry生成的applicationID和instanceIndex设置为eureka applicationID和instanceID。

CloudFoundryApplicationInitializer.kt

@Component
@Profile("cloud")
@EnableConfigurationProperties(CloudFoundryApplicationProperties::class)
class CloudFoundryApplicationInitializer {

private val log = LoggerFactory.getLogger(CloudFoundryApplicationInitializer::class.java)

@Autowired
private val applicationInfoManager: ApplicationInfoManager? = null

@Autowired
private val cloudFoundryApplicationProperties: CloudFoundryApplicationProperties? = null

@EventListener
fun onRefreshScopeRefreshed(event: RefreshScopeRefreshedEvent) {
    injectCfMetadata()
}

@PostConstruct
fun onPostConstruct() {
    injectCfMetadata()
}

fun injectCfMetadata() {

    if(this.cloudFoundryApplicationProperties == null) {
        log.error("Cloudfoundry Properties not set")
        return
    }

    if(this.applicationInfoManager == null) {
        log.error("ApplicationInfoManager is null")
        return
    }

    val map = applicationInfoManager.info.metadata
    map.put("applicationId", this.cloudFoundryApplicationProperties.applicationId)
    map.put("instanceId", this.cloudFoundryApplicationProperties.instanceIndex)

    }
}

CloudFoundryApplicationProperties.kt

@ConfigurationProperties("vcap.application")
class CloudFoundryApplicationProperties {
    var applicationId: String? = null
    var instanceIndex: String? = null
    var uris: List<String> = ArrayList()
}