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如何将解析对象传递到片段中的列表?

android

user6008330 · 技术社区 · 8 年前

我在tablayout中有2个片段,必须根据parse数据库的用户填写。

protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        Parse.initialize(this);
        ParseInstallation.getCurrentInstallation().saveInBackground();

        setContentView(R.layout.activity_main);
        .......

        ParseQuery<ParseObject> query = ParseQuery.getQuery("Items");
        // this will find the user.
        // then find the first instance
        query.findInBackground(new FindCallback<ParseObject>() {
            @Override
            public void done(List<ParseObject> objects, com.parse.ParseException e) {
                List<Items> 1List = new ArrayList<Items>();
                List<Items> 2List = new ArrayList<Items>();
                if (objects == null) {
                    Log.d("nothing found", "let's go ahead and create a new object.");
                    //ADD THE OBJECT AS A NEW OBJECT!!!!
                } else {
                    for(i=0;objects.size() > 0;i++) {
                        ParseObject parseObject = objects.get(i);
                        if(parseObject.getString("iduser").equals(ID_1)){

                            1List.add(objects.get(i));//ERROR HOW TO FIX?
                            /*THIS ERROR add
                            (com.dev.bob.recife3.persistence.Items)
                                    in ListÂ cannot be applied
                                    to
                            (com.parse.ParseObject)*/

                        }else{
                            2List.add(objects.get(i));//ERROR HOW TO FIX?
                            /*THIS ERROR add
                            (com.dev.bob.recife3.persistence.Items)
                                    in ListÂ cannot be applied
                                    to
                            (com.parse.ParseObject)*/
                        }
                        if (getFragmentRefreshListener1() != null) {
                            getFragmentRefreshListener1().onRefresh(new ItemsAdapter(getContext(), 1List));
                        }

                        if (getFragmentRefreshListener2() != null) {
                            getFragmentRefreshListener2().onRefresh(new ItemsAdapter(getContext(), 2List));
                        }
                        String test = parseObject.getString("name").toString();//JUST A TEST
                        Log.d("points found", "" + "");
                    }
                }
            }
        });
    }
    ........
    public class SectionPagerAdapter extends FragmentPagerAdapter {

        public SectionPagerAdapter(FragmentM2ger fm) {
            super(fm);
        }

        @Override
        public Fragment getItem(int position) {
            switch (position) {
                case 0:
                    return new 2TabFragment();
                case 1:
                    return new 1TabFragment();
                default:
                    return new 2TabFragment();
            }
        }

        @Override
        public int getCount() {
            return 2;
        }//retorna as duas abas estaticamente

        @Override
        public CharSequence getPageTitle(int position) {
            switch (position) {
                case 0:
                    return getString(R.string.2);
                case 1:
                    return getString(R.string.1);
                default:
                    return getString(R.string.2);
            }
        }
    }
    private Context getContext(){
        return this;
    }

    public FragmentRefreshListener getFragmentRefreshListener1() {
        return fragmentRefreshListener1;
    }

    public void setFragmentRefreshListener1(FragmentRefreshListener fragmentRefreshListener1) {
        this.fragmentRefreshListener1 = fragmentRefreshListener1;
    }

    private FragmentRefreshListener fragmentRefreshListener1;

    public interface FragmentRefreshListener{
        void onRefresh(ItemsAdapter itemsAdapter);
    }


    public FragmentRefreshListener2 getFragmentRefreshListener2() {
        return fragmentRefreshListener2;
    }

    public void setFragmentRefreshListener2(FragmentRefreshListener2 fragmentRefreshListener2) {
        this.fragmentRefreshListener2 = fragmentRefreshListener2;
    }

    private FragmentRefreshListener2 fragmentRefreshListener2;

    public interface FragmentRefreshListener2{
        void onRefresh(ItemsAdapter itemsAdapter);
    }
}

我如何获得片段,从解析中得到的列表? 如何传递这些数据,并使该列表显示在正确的片段中?代码中注释了错误,这是:

1列表。添加(objects.get(i)); Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 列表中的不能应用到

遵循数据库的图像:

2 回复 | 直到 8 年前

Shu Zhang 8 年前

您可以将查询从泛型更改为 ParseObject 进入 Items 这样地。

ParseQuery<Items> query = ParseQuery.getQuery(Items.class);
query.findInBackground(new FindCallback<Items>() {
    @Override
    public void done(List<Items> objects, com.parse.ParseException e) {
    }
});

这可以解决撞车问题。了解如何将数据传递到片段中。如果您先修复了崩溃,那么稍后可能会出现这种情况。

user6008330 user6008330 8 年前

我将适配器更改为接收parseobject:

List<ParseObject> 1List= new ArrayList<ParseObject>();
if (getFragmentRefreshListener1() != null) {
                            getFragmentRefreshListener1().onRefresh(new ItemsAdapter(getContext(), 1List));
                        }

                        if (getFragmentRefreshListener2() != null) {
                            getFragmentRefreshListener2().onRefresh(new ItemsAdapter(getContext(), 2List));
                        }

还有我的ItemsAdapter:

public ItemsAdapter(Context context, List<ParseObject> items) {
    super();
    this.context = context;
    this.itemsList = items;
}