代码之家 › 专栏 › 技术社区 › Jems

Laravel验证总是从API返回200 OK

validation laravel php

Jems · 技术社区 · 7 年前

200 OK

请求验证

class PostRequest extends FormRequest
{
    use Types;

    public function authorize()
    {
        return true;
    }

    public function rules()
    {
        // $auth = $this->request->user();
        return [
            'name'       => 'required|string|max:255',
            'country_id' => 'required|exists:countries,id',
            'city'       => 'required|max:255',
            'phone_no'   => 'required|regex:/[0-9]{10,13}/',
            'occupation' => 'required|max:255'
        ];
    }
}

发送器控制器

public function store(PostRequest $request)
{
    $auth = $request->user();

    $sender = Sender::create([
        'name'          => $request->name,
        'country_id'    => $request->country_id,
        'city'          => $request->city,
        'phone_no'      => $request->phone_no,
        'occupation'    => $request->occupation
    ]);
    return new Resource($sender);
}

当我发送请求时 name $validator->errors() 当我忘记输入名字的时候。我该怎么做?

路由和呼叫 :

Route::post('sender', 'V1\SenderController@store');

POST: localhost:8000/api/v1/sender

6 回复 | 直到 7 年前

Tspoon 6 年前

你应该确保你发送的请求与 Accept: application/json 标题。

如果没有这一点-Laravel将无法检测到它是一个API请求,也不会生成带有错误的422响应。

Xartrick 6 年前

FormRequest 要覆盖的对象 failedValidation

如前面评论部分所述,注入 表单请求

表单请求 和覆盖 .

<?php

namespace App\Http\Requests;

use Illuminate\Contracts\Validation\Validator;
use Illuminate\Foundation\Http\FormRequest;
use Illuminate\Http\Exceptions\HttpResponseException;
use Illuminate\Http\Response;

abstract class BaseFormRequest extends FormRequest
{
    /**
     * Get the validation rules that apply to the request.
     *
     * @return array
     */
    abstract public function rules(): array;

    /**
     * Determine if the user is authorized to make this request.
     *
     * @return bool
     */
    abstract public function authorize(): bool;

    /**
     * Handle a failed validation attempt.
     *
     * @param  Validator  $validator
     *
     * @return void
     */
    protected function failedValidation(Validator $validator): void
    {
        $errors = $validator->errors();

        throw new HttpResponseException(response()->json([
            'errors' => $errors
        ], Response::HTTP_UNPROCESSABLE_ENTITY));
    }
}

BaseFormRequest

https://medium.com/@Sirolad/laravel-5-5-api-form-request-validation-errors-d49a85cd29f2

Jems 7 年前

我通过在我的系统中添加更多的代码来解决这个问题 PostRequest.php

public $validator = null;
protected function failedValidation($validator)
{
    $this->validator = $validator;
}

并用控制器显示错误信息

if (isset($request->validator) && $request->validator->fails()) {
        return response()->json([
            'error_code'=> 'VALIDATION_ERROR', 
            'message'   => 'The given data was invalid.', 
            'errors'    => $request->validator->errors()
        ]);
    }

Md. Mohaiminul Hasan 4 年前

如果你是从邮递员的要求,然后总是检查标题

Accept = 'application/json'

George Hanson 7 年前

你的邮递员回复是寄回 welcome.blade.php Resource

检查您提出请求的路线是否绝对正确。同时检查您是否正在进行 POST GET

-2

Shailendra Gupta 7 年前

保存前必须验证请求

public function store(PostRequest $request)
{
    $auth = $request->validate();

    if($auth->fails())
    {
         return response()->json($auth->errors());
    }
    $sender = Sender::create([
        'name'          => $request->name,
        'country_id'    => $request->country_id,
        'city'          => $request->city,
        'phone_no'      => $request->phone_no,
        'occupation'    => $request->occupation
    ]);
     return new Resource($sender);

}