为什么postfixed的优先级高于前缀?[副本]

这与优先级无关。(此处)在预增量中,分配的值是副作用发生之前的值。 对于预增量,它将是副作用后的值。

int i = 10;
int j = i++;

i 是10。所以 j=10 执行这两条语句之后。

int i = 10;
int j = ++i;

这里的值为11。因为增量先完成,然后分配。

Linux操作系统 manual 第页,共页 operator 定义为 same priority 对于前置/后置 increment .

! ~ ++ -- + - (type) * & sizeof      right to left

先分配增量后规则,然后再分配增量

int j = i++;// here first whatever i value is there that will be assigned to j

预增量规则是先增量,然后分配

int j = ++i;//++i itself will change i value & then modfied value will assign to j.

例如,考虑以下示例

#include<stdio.h>
int main()
{
        int x = 10;
        int *p = &x;// assume p holds 0x100
        printf("x = %d *p = %d p = %p\n",x,*p,p);
        ++*p++;
        /** in above statement ++ and * having same precedence,then you should check assocaitivity which is R to L
          So start solving from Right to Left, whichever operator came first , solve that one first 
          first *p++ came , again solve p++ first, which is post increment,so address will be same 
         *0x100  means = 10
         now ++10 means = 11
         **/
        printf("x = %d *p = %d p = %p\n",x,*p,p);
}