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随机数游戏C

srand do-while while-loop for-loop c

Djeter277 · 技术社区 · 12 年前

虽然我第一次玩这个游戏很顺利;第二次它只给你两条生命。。。我已经试图改变生命的数量,但仍然无法弄清楚我做错了什么。

//C_program_random_number_game

#include<stdio.h>
#include<time.h>
#include <stdlib.h>

int main()
{

   srand(time(NULL));
   int num1,x = 0;
   char game, cont, replay;

   printf("Would you like to play a game? : ");
   scanf("%c",&game);

  if (game == 'y' || game == 'Y')
  {
    printf("\nThe rules are simple. You have have 5 tries to guess the computers number. \n \n If you succeed you win the game, if you dont you lose the game. Good luck!");
    do
    {
        int r = rand()%5 +1;
        printf("\n\nEnter a number between 1 and 5 : ");
        scanf("\n%d",&num1);
        x++;
        if(num1 > 0 && num1 < 5)  
        {

            do
            {
             if(num1 < r)
                {
                    printf("\nClose! try a little higher... : ");
                    x++; 
                }
              else if (num1 > r)
                {
                    printf("\nClose! try a little lower...: ");
                    x++; 
                }
                scanf("%d",&num1);

            }while(num1!=r && x <3); 

            if(num1 == r) 
            {
                printf("\nWinner! >> you entered %d and the computer generated %d! \n",num1, r);
            }
            else if(num1 != r)
            {
                printf("\nBetter luck next time!");
            }
            printf("\n\nWould you like to play again? (y or n) : ");
            scanf("\n%c",&replay);
        }
            else
        {
            printf("Sorry! Try again : ");
            scanf("%d",&num1);
        }

    }while(replay == 'y'|| replay == 'Y');

}
else if (game == 'n' || game == 'N')
{
    printf("Okay, maybe next time! ");
}
else
{
    printf("Sorry, invalid data! ");
}
return 0;

}

2 回复 | 直到 12 年前

MrHappyAsthma 12 年前

你的代码有各种各样的问题(大多数都是编程方面的小问题)。大多数错误都是你想通过这个问题做什么以及你打印什么()中的错别字。

实际上,这段代码将在1-25之间随机,接受任何有效int的输入,看看是否匹配,然后只给你5次尝试。(我没有添加错误检查来强制输入在1-25之间。这可能应该加上。)

我在下面的代码中添加了所有的更改,并按照printf()中的内容进行了修改。

注:由于我已经指出了我的更改,请参见我上面的评论。我还对它进行了格式化,使其更易于阅读。

注2:我使用在线编译器快速完成了这一操作。如果你发现这有什么问题或不按你的意愿工作,请在下面评论,我会解决它。

// C_program_random_number_game

#include<stdio.h>
#include<time.h>
#include <stdlib.h>

int main()
{

    srand(time(NULL));
    int num1,x = 0;
    char game, cont, replay;

    printf("Would you like to play a game? : ");
    scanf("%c",&game);

    if (game == 'y' || game == 'Y')
    {
        printf("\nThe rules are simple. You have have 5 tries to guess the                 computers number. \n \n If you succeed you win the game, if you dont you lose the game. Good luck!");

        do
        {
            int r = rand()%25 +1;

            printf("\n\nEnter a number between 1 and 25 : ");
            scanf("%d",&num1);

            do
            {
                printf("r = %d\n", r);

                if(num1 < r)
                {
                    printf("\nClose! try a little higher... : ");
                    x++; //Increment x if wrong guess
                }
                else if (num1 > r)
                {
                    printf("\nClose! try a little lower...: ");
                    x++; //Increment x if wrong guess
                }

                scanf("%d",&num1);
            }while(num1!=r && x < 5); //If x is 5 or more, they ran out of guesses (also, you want an && not an ||)

           if(num1 == r) //Only print "winner" if they won!
           {
               printf("\nWinner! >> you entered %d and the computer generated %d! \n",num1, r);
           }

            printf("\nWould you like to play again? (y or n) : ");
            scanf("\n%c",&replay);
        }while(replay == 'y'|| replay == 'Y');
    }

    printf("Thanks for playing! ");

    if (game == 'n' || game == 'N')
    {
        printf("Okay, maybe next time! ");
    }
    return 0;
}

syncsynchalt 12 年前

有两个问题。第一个是,当数字匹配时,您不会跳出“for”循环。因此,比赛只在每三次猜测时进行检查。

第二个问题是逻辑检查:

}while(num1!=r || x <= 3);

我们看到,如果for循环提前中断,这将变成“真”。