删除给定NSRange的子字符串

这也可以做到:

NSString *result = [baseString stringByReplacingCharactersInRange:range withString:@""];

您可以将子字符串放在范围的开头,将子字符串放在范围的结尾,并将它们连接在一起。

NSString* stringByRemovingRange(NSString* theString, NSRange theRange) {
  NSString* part1 = [theString substringToIndex:theRange.location];
  NSString* part2 = [theString substringFromIndex:theRange.location+theRange.length];
  return [part1 stringByAppendingString:part2];
}

the -deleteCharactersInRange: method 就是这样。

NSString* stringByRemovingRange(NSString* theString, NSRange theRange) {
  NSMutableString* mstr = [theString mutableCopy];
  [mstr deleteCharactersInRange:theRange];
  return [mstr autorelease];
}

也许你可以用这段代码: 这将查看一个包含代码的列表:a、b、c、d,。。。 如果最后一个代码是d。。它将添加代码e。

NSString *alphabet = @"ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    NSUInteger i, count = [lead count];
    for (i = 0; i < count; i++) {
        Listings * l = [lead objectAtIndex:i];
        NSUInteger location = [alphabet rangeOfString:l.code].location + 1;
        if(!([l.code isEqualToString:@"X"]))
        {
            if(!(location -1 == i))
            {
                NSRange range = {location - 2,1};
                NSString *newCode = [alphabet substringWithRange:range];
                l.code = newCode;

            }
        }