如何使用xslt添加“join”xml文件?

这是我真正问题的简化版本,但我已经测试过了,得到了相同的结果;

<?xml version="1.0" encoding="UTF8"?>
<fieldList>
<sourceField name="SourceTime">
<fid>REC_TIME</fid>
</sourceField>
</fieldList>

查找.xml

<?xml version="1.0" encoding="UTF-8"?>
<data>
<field  name="REC_TIME" fid_type="DATE"/>
</data>

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="UTF-8" media-type="text/plain"/>
<xsl:variable name="fieldDict" select="'lookup.xml'" />
<xsl:template match="/fieldList/*[fid]">
<xsl:variable name="id" select="current()"/>
<xsl:value-of select="$id"/>
<xsl:for-each select="document($fieldDict)/data/field[@name = $id]">
<xsl:value-of select="@type"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

现在,如果我将xpath改为[@name],我将得到

REC_TIME
MONKEY

我在Linux上用xsltproc测试这个

xsltproc --version
Using libxml 20705, libxslt 10124 and libexslt 813
xsltproc was compiled against libxml 20632, libxslt 10124 and libexslt 813
libxslt 10124 was compiled against libxml 20632
libexslt 813 was compiled against libxml 20632