Django:路由相同的模型,但不同的类别字段来分隔URL

我有以下模型和URL路由。有一个发布模型,我想根据类别路由到不同的URL。有没有办法通过传递额外的信息 app/urls.py ?

在 app/posts/models.py

class Post(models.Model):
    author = ...
    title = ...
    body = ...
    category = models.CharField()

在 APP/URLS.Py

urlpatterns = patterns(
    '',
    (r'^blog/', include('posts.urls'), {'category': 'blog'}),
    (r'^school/', include('posts.urls'), {'category': 'school'}),
)

我的理解是 app/posts/urls.py

from models import Post

queryset = Post.objects.order_by('-pub_date')

urlpatterns = patterns(
    'django.views.generic.list_detail',
    url(r'^$', 'object_list',
        {'queryset': queryset.filter(category=!!!!!!)}
        name="postRoot"),

    url(r'^(?P<slug>[-\w]+)/$', 'object_detail',
        {'queryset': queryset.filter(category=!!!!!!)},
        name="postDetail")
    )