我试图创建一个以uiviewcontroller为函数的函数。原因是可以传递多个自定义viewcontrollers。下面是我的当前函数,它可以工作,但使用switch语句和枚举:
enum controllerTypes {
case First, Second
}
extension UIViewController {
func presentViewController(storyBoardName: String, storyBoardIdentifier: String, controllerType: controllerTypes, completion:(() -> Void)?) {
switch controllerType {
case .First:
let firstVC = UIStoryboard(name: storyBoardName, bundle: nil).instantiateViewController(withIdentifier: storyBoardIdentifier) as? FirstViewController
if let firVC = firstVC {
self.present(firVC, animated: true, completion: nil)
}
case .Second:
let secondVC = UIStoryboard(name: storyBoardName, bundle: nil).instantiateViewController(withIdentifier: storyBoardIdentifier) as? SecondViewController
if let secVC = secondVC {
self.present(secVC, animated: true, completion: nil)
}
}
completion?()
}
}
我不想为参数传递'controllerTypes'枚举,而是要传递任何类型的uiviewcontroller,当我尝试执行此操作时,出现以下错误:
func presentViewController(storyBoardName: String, storyBoardIdentifier: String, controllerType: UIViewController, completion:(() -> Void)?) {
let sampleVC = UIStoryboard(name: storyBoardName, bundle: nil).instantiateViewController(withIdentifier: storyBoardIdentifier) as? controllerType//error - use of undeclared type 'controllerType'
if let samVC = sampleVC {
self.present(samVC, animated: true, completion: nil)
}
}
你知道这样做是否可行吗?