如果文件名缺少字符串,请使用批处理文件重命名文件

    for /f "delims=" %%a in ('dir /b /a-d *.csv ^|findstr /iv "zac"') do echo ren "%%~a" "%%~na Zac%%~xa"

查看输出并移除 echo 如果它看起来不错。
注意:如果文件已经存在 ren 失败,您会收到一条错误消息。

这应该起作用:

@echo off
: create variable to track number of files renamed
set filesRenamed=0
: loop through csv files and call Rename routine
for %%f in (*.csv) do call :Rename "%%f" filesRenamed
: output results
echo %filesRenamed% files renamed
: clear variables
set filesRenamed=
set tmpVar=
: Goto end of file so we don't call rename an extra time
goto :eof

:Rename
: need a local environment variable with filename for manipulation
set tmpVar=%1
: remove the closing quotes
set tmpVar=%tmpVar:~0,-1%
: compare the last 8 characters and rename as necessary
if /I NOT "%tmpVar:~-8%" EQU " Zac.csv" (
    : use original file name parameter which is already quoted
    ren %1 ???????????????????????????????" Zac.csv"
    : increment the renamed file count
    set /A %2=%2+1
)

看见 this other post 以便很好地描述批处理文件中的子字符串处理。

使用 renamer ,这些输入文件:

Test File1 Zac.csv
Test File2.csv
Test File3.csv
Test File4.xls
Test File5 Zac.csv

使用此命令:

$ renamer --regex --find '(Test File\d)(\.\w+)' --replace '$1 Zac$2'  *

导致以下新文件名:

Test File1 Zac.csv
Test File2 Zac.csv
Test File3 Zac.csv
Test File4 Zac.xls
Test File5 Zac.csv

如果你还需要帮助,请告诉我。