查询graphiql leads apollo error forward不是函数

我有一个带有graphql的快速后端,当我访问 /graphiql 手动执行一些搜索。我的反应前端试图在后端执行搜索。以下代码应异步执行查询:

const data = await this.props.client.query({
    query: MY_QUERY,
    variables: { initials: e.target.value }
});
console.log(data);

在哪里? MY_QUERY 是以前定义的,表示一个查询,我知道该查询有效,并且已在其上进行了测试 石墨化 . 要在我的react组件中执行此操作,我将其导出为 export default withApollo(MyComponent) 所以它有 client 变量在 props .

在 index.js 我通过阿波罗定义的文件连接到 石墨化 为了执行查询:

//link defined to deal with errors, this was found online
const link = onError(({ graphQLErrors, networkError }) => {
    if (graphQLErrors)
        graphQLErrors.map(({ message, locations, path }) =>
        console.log(
            `[GraphQL error]: Message: ${message}, Location: ${locations}, Path: ${path}`,
        ),
        );

    if (networkError) console.log(`[Network error]: ${networkError}`);
});

//the httpLink to my GraphQL instance, BASE_URL is defined elsewhere
const httpLink = new HttpLink({
    uri: BASE_URL,
    headers: {
    },
});

//here I define the client linking the GraphQL instance, the cache, and error handling
const client = new ApolloClient({
    link: httpLink,
    cache,
    link
});

在执行上述查询时, link 处理错误的变量,我收到一个 400 Bad Request 从服务器( ApolloError.js:37 Uncaught (in promise) Error: Network error: Response not successful: Received status code 400 )由于这并没有告诉我更多,在StackOverflow和Apollo网页上,我发现了上面的错误声明 [Network error]: TypeError: forward is not a function . 这个错误是什么意思?我该如何解决它?

谢谢!