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shell脚本中的%和%有什么区别?

scripting shell bash linux

3

Naveen Dennis · 技术社区 · 8 年前

在bash脚本中,当 t="hello.txt" 二者都

${t%%.txt} 和 ${t%.txt} 退货 "hello"

同样的道理 ${t##*.} 和 ${t#*.} 退货 "txt" .

他们之间有区别吗?它们是如何工作的?

2 回复 | 直到 8 年前

1

2

Benjamin W. 8 年前

简而言之, %% 尽可能地移除, % 尽可能少。

# t="hello.world.txt"
# echo ${t%.*}
hello.world
# echo ${t%%.*}
hello

从bash手册:

'${PARAMETER%WORD}'
'${PARAMETER%%WORD}'
     The WORD is expanded to produce a pattern just as in filename
     expansion.  If the pattern matches a trailing portion of the
     expanded value of PARAMETER, then the result of the expansion is
     the value of PARAMETER with the shortest matching pattern (the '%'
     case) or the longest matching pattern (the '%%' case) deleted.  If
     PARAMETER is '@' or '*', the pattern removal operation is applied
     to each positional parameter in turn, and the expansion is the
     resultant list.  If PARAMETER is an array variable subscripted with
     '@' or '*', the pattern removal operation is applied to each member
     of the array in turn, and the expansion is the resultant list.

2

1

Benjamin W. 8 年前

${string%substring}
删除最短匹配项 $substring 从的后面 $string .

例如:

# Rename all filenames in $PWD with "TXT" suffix to a "txt" suffix.
# For example, "file1.TXT" becomes "file1.txt" . . .

SUFF=TXT
suff=txt

for i in $(ls *.$SUFF)
do
  mv -f $i ${i%.$SUFF}.$suff
  #  Leave unchanged everything *except* the shortest pattern match
  #+ starting from the right-hand-side of the variable $i . . .
done ### This could be condensed into a "one-liner" if desired.

${string%%substring}
删除最长匹配项 $子字符串 从的后面 $string .

stringZ=abcABC123ABCabc
#                    ||     shortest
#        |------------|     longest

echo ${stringZ%b*c}      # abcABC123ABCa
# Strip out shortest match between 'b' and 'c', from back of $stringZ.

echo ${stringZ%%b*c}     # a
# Strip out longest match between 'b' and 'c', from back of $stringZ.