可可:测量按键之间的时间?

NSDate *start = [NSDate date];
// do the thing you are timing
NSDate *stop = [NSDate date];

NSTimeInterval duration = [start timeIntervalSinceDate:stop];

也许更好的方法是提取与每个按键相关的NSEvent,并比较它们的-timestamp属性的差异。

获取当前时间,然后减去上一个当前时间。看 -[NSDate timeIntervalSinceDate:] .

• 您可以设置计时器,在用户停止键入后执行某项操作X的时间,然后在每次用户键入某项操作时重新启动该时间,从而延迟计时器的到期时间。

• 您可以选择在最后一次按键时启动计时器,持续X时间。到期时,您可以检查上次击键的时间戳,该时间戳是您在上次击键时保存的,然后您可以从(超时-上次击键时间)的时间量开始重新启动计时器。到期后再次检查。然后,在每次按键时,如果计时器正在运行,则仅更新最后一次按键的时间戳。..

我认为你应该用线来做这件事。为按键创建线程,在每个线程中,您可以计算按键之间的时间。如需更多解释,请观看我的视频,了解这个确切的解决方案。

https://www.youtube.com/watch?v=sDGYM8LeZh8

请参阅下面的代码:

import keyboard # keyboard library
import string   # string for capturing keyboard key codes
import time     # for capturing time

from threading import * # threads for keypresses

# get the keys
keys = list(string.ascii_lowercase)

# key listener
def listen(key):
    while True:
        global timeda   # global variable for storing time for 1st keypress
        global newda    # global variable for storing time for next keypress

        keyboard.wait(key)  # when key is presses

        # check if variables are defined
        try:
            timeda
            newda

        # this will run for the first keypress only so assign initial time to variable

        except NameError:
            timeda = time.time()
            newda  = time.time()
            print("First key is pressed at "+str(round(newda,2)))
            print('\n==========\n')

        # for all keypresses except for the first will record time here
        else:
            newda = time.time()         # assign time for next keypressed
            newtime = newda - timeda    # get difference between two keys presses

            # just to test time of first keypress
            print("Previous keypress was at "+str(round(timeda,2)))

            # just to test time of next keypress
            print("Current keypress is at "+ str(round(newda,2)))

            # convert time into seconds
            newtime = newtime % 60

            print("Difference between two keypresses is "+str(round(newtime,2)))
            print('\n==========\n')     # need some space for printing difference 
            timeda = time.time()

# creating threads for keys and assigning event and args 
threads = [Thread(target=listen, kwargs={'key':key}) for key in keys]

# calling each thread
for thread in threads:
    thread.start()


# thats it