鸡肉方案-csc无法定位“chicken.foreign.import.so”

;; add1.ss

(import foreign)

(define add-1
  (foreign-lambda* long ((unsigned-long x))
                   "
                   long n = 1
                   C_return(n + x);))

(print (add-1 (read)))

这个 foreign 我感兴趣的图书馆肯定存在。

find /usr/local | grep chicken | grep foreign | grep lib
/usr/local//Cellar/chicken/5.0.0/lib/chicken/9/chicken.foreign.import.so

但是,通过 csc add1.ss 没有旗帜 CSC_OPTIONS 环境变量产生:

$ csc add1.ss
Syntax error (import): cannot import from undefined module

        foreign

        Expansion history:

        <syntax>          (##core#begin (import foreign))
        <syntax>          (import foreign)      <--

Error:shell command terminated with non-zero exit status 17920:
'/usr/local/Cellar/chicken/bin/5.0.0/bin/chicken' 'add1.ss' -output-file 'add1.c'

$ chicken add1.ss -output-file add1.c

产生同样的故障。在chicken手册页中,似乎与路径管理相关的唯一命令行选项是 -include-path . 我试过下面的咒语,它们都产生了同样的错误

$ chicken add1.ss -output-file add1.c -include-path /usr/local/Cellar/chicken/5.0.0/lib/chicken/9/chicken.foreign.import.so
$ chicken add1.ss -output-file add1.c -include-path /usr/local/Cellar/chicken/5.0.0/lib/chicken/9
$ chicken add1.ss -output-file add1.c -include-path /usr/local/Cellar/chicken/5.0.0/lib/chicken
$ chicken add1.ss -output-file add1.c -include-path /usr/local/Cellar/chicken/5.0.0/lib
$ chicken add1.ss -output-file add1.c -include-path /usr/local/Cellar/chicken/5.0.0

我还试着通过考试 chicken.foreign.import.so

$ chicken add1.ss -output-file add1.c /usr/local/Cellar/chicken/5.0.0/lib/chicken/9/chicken.foreign.import.so 

正确的指挥方式是什么 chicken 或者编译器驱动程序 csc 在下的目录中查找Chicken的内部库 /usr/local/Cellar/chicken/... ?