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反序列化字符串时发生org.codehaus.jackson.JsonParseException

fasterxml objectmapper deserialization java

0

Aarish Ramesh · 技术社区 · 7 年前

{13714974:{获取url: https://example.com/get “,发布url: https://example.com/post },13743772:{获取url: " https://example.com/get https://example.com/post

ObjectMapper mapper = new ObjectMapper();
        mapper.configure(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
        Map<String, Map<String, String>> cmMappings = mapper.readValue(content, Map.class);

当我使用codehaus jackson ObjectMapper并尝试反序列化它时,我得到了一个异常,

Exception in thread "main" org.codehaus.jackson.JsonParseException: Unexpected character ('1' (code 49)): was expecting either valid name character (for unquoted name) or double-quote (for quoted) to start field name
 at [Source: java.io.StringReader@7cdbc5d3; line: 1, column: 3]
    at org.codehaus.jackson.impl.JsonParserBase._constructError(JsonParserBase.java:651)
    at org.codehaus.jackson.impl.JsonParserBase._reportError(JsonParserBase.java:635)
    at org.codehaus.jackson.impl.JsonParserBase._reportUnexpectedChar(JsonParserBase.java:576)
    at org.codehaus.jackson.impl.ReaderBasedParser._handleUnusualFieldName(ReaderBasedParser.java:385)
    at org.codehaus.jackson.impl.ReaderBasedParser._parseFieldName(ReaderBasedParser.java:268)
    at org.codehaus.jackson.impl.ReaderBasedParser.nextToken(ReaderBasedParser.java:118)

Exception while deserialising because of hyphen in field names

我也尝试了FasterXMLObjectMapper,但它不起作用

1 回复 | 直到 7 年前

1

0

Ashish Kamble 7 年前

这就是我们如何反序列化上面的字符串

try {    
    ObjectMapper mapper = new ObjectMapper();
    ClassPathResource resource = new ClassPathResource("resourceFile");
    mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
    mapper.configure(com.fasterxml.jackson.core.JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
    TypeReference<HashMap<String, Map<String, String>>> typeRef = new TypeReference<HashMap<String, Map<String, String>>>() {};
    cmMappings = mapper.readValue(resource.getInputStream(), typeRef);
} catch (Exception ex) {
   // log error    
}