代码之家 › 专栏 › 技术社区 › Leo Wiki

org.jivesoftware.smack.SmackException$NoResponseException

xmpp android

Leo Wiki · 技术社区 · 10 年前

我正在尝试使用XMPP服务器(Openfire)在我的Android应用程序中实现聊天(1对1&组),但在连接时,我遇到了以下异常 " org.jivesoftware.smack.SmackException$NoResponseException “下一行

" connection.connect(); "

我检查了MyConstants。主持人,MyConstants。端口,MyConstants。服务是正确的,但不知道为什么我会得到这个错误。

以下是我目前的代码,请检查并帮助我解决此问题。

// Create a connection
        ConnectionConfiguration connConfig = new ConnectionConfiguration(MyConstants.HOST, MyConstants.PORT, MyConstants.SERVICE);
        connConfig.setDebuggerEnabled(true);
        connConfig.setSecurityMode(SecurityMode.disabled);

        connection = new XMPPTCPConnection(connConfig);

        try
        {
            connection.connect();
            Log.e("XMPPChatDemoActivity",  "[SettingsDialog] Connected to "+connection.getHost());

            if(connection.isConnected())
            {
                Map<String, String> attributes = new HashMap<String, String>();
                attributes.put("username", userId);
                attributes.put("password", MyConstants.PASSWORD);
                Registration reg = new Registration();
                reg.setType(IQ.Type.SET);
                reg.setTo(connection.getServiceName());
                reg.setAttributes(attributes);

                connection.sendPacket(reg);

                connection.login(userId, MyConstants.PASSWORD);
                Log.e("XMPPChatDemoActivity",  "Logged in as" + connection.getUser());
                //Set the status to available
                Presence presence = new Presence(Presence.Type.available);
                connection.sendPacket(presence);                   
                Roster roster = connection.getRoster();
                Collection<RosterEntry> entries = roster.getEntries();
                for (RosterEntry entry : entries) 
                {
                    Log.d("XMPPChatDemoActivity",  "--------------------------------------");
                    Log.d("XMPPChatDemoActivity", "RosterEntry " + entry);
                    Log.d("XMPPChatDemoActivity", "User: " + entry.getUser());
                    Log.d("XMPPChatDemoActivity", "Name: " + entry.getName());
                    Log.d("XMPPChatDemoActivity", "Status: " + entry.getStatus());
                    Log.d("XMPPChatDemoActivity", "Type: " + entry.getType());
                    Presence entryPresence = roster.getPresence(entry.getUser());
                    Log.d("XMPPChatDemoActivity", "Presence Status: "+ entryPresence.getStatus());
                    Log.d("XMPPChatDemoActivity", "Presence Type: " + entryPresence.getType());

                    Presence.Type type = entryPresence.getType();
                    if (type == Presence.Type.available)
                        Log.d("XMPPChatDemoActivity", "Presence AVIALABLE");
                    Log.d("XMPPChatDemoActivity", "Presence : " + entryPresence);
                }
            }

        } 
        catch (XMPPException ex) 
        {
            Log.e("XMPPChatDemoActivity",  "[SettingsDialog] Failed to connect to "+ connection.getHost());
            Log.e("XMPPChatDemoActivity", ex.toString());
            connection = null;
        } 
        catch (SmackException e)
        {
            Log.e("Exception: ", e.toString());
            e.printStackTrace();
        } 
        catch (IOException e) 
        {
            Log.e("Exception: ", e.toString());
            e.printStackTrace();
        }

3 回复 | 直到 10 年前

Dnyanesh M 9 年前

我以前也遇到过同样的问题,请确保您没有交换MyConstants。主机,MyConstants.PORT

Mitch 9 年前

这对我很有用: Roster.setRosterLoadedAtLoginDefault(假);

-1

Mack94 10 年前

我在我的项目中使用了Smack的旧版本,但请参考这个,也许它会对你有所帮助。

在openfire中,我创建了登录名为userName,pass为密码的示例用户。

下面的代码将引发类似的异常,如:

    config.setSecurityMode(ConnectionConfiguration.SecurityMode.disabled)
            .setServiceName(serviceName)
            .setHost(serverAddress)
            .setPort(serverPort)
            .setDebuggerEnabled(debugMode);

    connection = new XMPPTCPConnection(config.build());
    connection.connect();

结果如下:

  org.jivesoftware.smack.SmackException$NoResponseException: No response received within reply timeout. Timeout was 5000ms (~5s). Used filter: AndFilter: (FromMatchesFilter (full): a0c88176-be28-4318-acb7-d08fd3803ef5@conference.makowka/jacek, StanzaTypeFilter:       org.jivesoftware.smack.packet.Presence).
  org.jivesoftware.smack.SmackException$NoResponseException: No response received within reply timeout. Timeout was 5000ms (~5s). Used filter: AndFilter: (FromMatchesFilter (full): a0c88176-be28-4318-acb7-d08fd3803ef5@conference.makowka/jacek, StanzaTypeFilter: org.jivesoftware.smack.packet.Presence).

但在转变为这一点之后:

    config.setSecurityMode(ConnectionConfiguration.SecurityMode.disabled)
            .setServiceName(serviceName)
            .setHost(serverAddress)
            .setPort(serverPort)
            .setDebuggerEnabled(debugMode);

    config.setUsernameAndPassword(userName, password);
    connection = new XMPPTCPConnection(config.build());
    connection.connect().login();

一切都很好!所以请尝试创建用户,在配置实例中设置此用户并调用登录方法。因此,解决的关键在于:

    connection.connect().login();

希望对您有所帮助!:-)