spring boot-应用程序在oracle出错的情况下启动

spring.datasource.platform=uat
spring.jpa.database=Oracle
spring.jpa.hibernate.ddl-auto=update
spring.datasource.initialization-mode=always
spring.jpa.database-platform=org.hibernate.dialect.Oracle10gDialect
spring.jpa.show-sql=true
spring.datasource.url=url
spring.datasource.username=username
spring.datasource.password=password
spring.datasource.driver-class-name=oracle.jdbc.OracleDriver
spring.jpa.properties.hibernate.enable_lazy_load_no_trans=true

@Entity 被扫描并创建了一个模式我得到了一个oracle错误( ORA-00904: : invalid identifier )尽管有设置,应用程序仍会继续启动 spring.datasource.continue-on-error=false

编辑

我不能张贴的实体,但它的形式

@Entity
@Table(name="foo")
public class Foo {
      @Id 
      @GenericGenerator(name="idGen", strategy="increment")
      @GeneratedValue(generator="idGen")
      @Column(name="id",nullable=false)
      private Long id;

      @Column(name="userid",nullable=false)
      private String user;

      /*getter and setter lombok annotations omitted for readability*/
 }

谢谢你的帮助