如何重复连接字符串?

这个合适吗

NSMutableString *s1 = [[NSMutableString alloc] initWithString:@""];
NSString *s2 = @"abc";

for(NSInteger idx = 0; idx < 10; ++idx) {
   [s1 appendString:s2];
}

...

[s1 release];

尽管@thatsdisgusting给出了一个完美的答案,但这里有一条捷径:

NSMutableString *a = [NSMutableString stringWithCapacity:0];
NSString *pad = @"abc";
NSString *ret = [a stringByPaddingToLength:10*[pad length] withString:pad
                                                           startingAtIndex:0];

滥用 stringByPaddingToLength .