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使用使用scala的json play分析S3上的json文件

play-json playframework amazon-s3 apache-spark scala

0

user1393608 · 技术社区 · 7 年前

我想使用json play fromework从S3访问一个json文件

val creds:DefaultAWSCredentialsProviderChain = new DefaultAWSCredentialsProviderChain
val s3Client = new AmazonS3Client(creds)
val uri: AmazonS3URI = new AmazonS3URI(conf_file)
val s3Object: S3Object = s3Client.getObject(uri.getBucket, uri.getKey)

val json = Json.parse(s3Object.getObjectContent)

val mylist = (json \ "mydata").get.as[List[JsValue]]


But this line gives an error no such element "mydata"

Can anyone tell how to access a json file and read its contents using json play in scala.

I am able to access same file from local machine, as well as fetch contents of "mydata" from within json

1 回复 | 直到 7 年前

1

0

Rex 7 年前

您是否尝试先打印对象并检查它是否正确格式化为JSON,因为我觉得一切都正常。

val json: JsValue = Json.parse("""{
  "mydata": [
    {"first": "aa"},
    {"second": "bb"},
    {"third": "cc"}
  ]
}""")

(json \ "mydata").asOpt[Seq[JsValue]].getOrElse(None)

尝试实现类似的东西。