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将URL解析为命令

zsh

Ahmad Ismail · 技术社区 · 6 年前

% https://github.com/chmln/sd.git        
zsh: no such file or directory: https://github.com/chmln/sd.git

我想要 https://github.com/chmln/sd.git

git clone https://github.com/chmln/sd.git
cd sd

我试过了 preexec 钩子。

preexec () { 
    print ">>>preexec start<<<"
    # print -l ${(qqq)@}

    if  [[ ${(qqq)@} =~ ^https.* ]]
    then
    echo URL
    fi
    print ">>>preexec end<<<"

}

输出是

% https://github.com/chmln/sd.git
>>>preexec start<<<
>>>preexec end<<<
zsh: no such file or directory: https://github.com/chmln/sd.git

0 回复 | 直到 6 年前

Ahmad Ismail 6 年前

function _accept-line-with-url {

    if  [[ $BUFFER =~ ^https.*git ]]
    then

        echo $BUFFER >> $HISTFILE
        fc -R

        BUFFERz="git clone $BUFFER && cd $(basename $BUFFER .git)"
        zle .kill-whole-line
        BUFFER=$BUFFERz
        zle .accept-line
    else 
        zle .accept-line
    fi 
}

zle -N accept-line _accept-line-with-url

现在您可以在提示符中粘贴github url,它将克隆repo。

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