PHP preg\u replace add括号

按照以下方式制作图案和替换品:

$str = "xxx - 12, ABC DEF GHI";
$pattern = "/([A-Z]+ - [0-9]+,) ([A-Z\s]+)/i";
$replace = "$1 ($2)";
echo preg_replace($pattern,$replace,$str);

Demo

您可以尝试:

$str = preg_replace('~\d,\h*\K.*\S~', '($0)', $str);

图案细节:

~         # pattern delimiter
\d,       # a digit followed by a comma
\h*       # zero or more horizontal whitespaces
\K        # start the match result at this position
.* \S     # zero or more characters until the last non-whitespace character
~

在替换字符串中 $0 \K 在该模式中,整个匹配只是由 .*\S .