Swift-如何比较枚举与相关值?

我正在尝试编写一个XCTest来验证与枚举中关联值的比较。

enum MatchType : Equatable {
    case perfectMatch(Int, Int)
    case lowerMatch(Int, Int)
    case higherMatch(Int, Int)
}

extension MatchType {
    static func == (lhs: MatchType, rhs: MatchType) -> Bool {
        switch (lhs, rhs) {
        case (.perfectMatch, .perfectMatch):
            return true
        case (.lowerMatch, .lowerMatch):
            return true
        case (.higherMatch, .higherMatch):
            return true
        default:
            return false
        }
    }
}

如何进行比较以确保正确的枚举,而不知道具体的int是什么?

在我的测试中,我会这样做:

func testPerfectMatch() {
        let orders = [6]
        let units = 6

        let handler = SalesRuleHandler(orders: orders, units: units)

        XCTAssertEqual(handler.matchType!, MatchType.perfectMatch(0, 0))
    }

这个 SalesRuleHandler 决定返回枚举的完全匹配、低匹配还是高匹配,

class SalesRuleHandler {

private var orders: [Int]
private var units: Int
var matchType: MatchType?

init(orders: [Int], units: Int) {
    self.orders = orders
    self.units = units
    self.matchType = self.handler()
}

private func handler() -> MatchType? {
    let rule = SalesRules(orders)

    if let match = rule.perfectMatch(units) {
        print("Found perfect match for: \(units) in orders \(rule.orders) at index: \(match.0) which is the value \(match.1)")
        return MatchType.perfectMatch(match.0, match.1)
    }
    else {
        if let match = rule.lowerMatch(units) {
            print("Found lower match for: \(units) in orders \(rule.orders) at index: \(match.0) which is the value \(match.1)")
            return MatchType.lowerMatch(match.0, match.1)
        }
        else {
            if let match = rule.higherMatch(units) {
                return MatchType.higherMatch(match.0, match.1)
            }
        }
    }
    return nil
}

我想做的是:

orders units 我应该可以测试 matchType 是 perfect , lower 或 higher

然而,在我的测试中,我必须写下如下内容:

XCTAssertEqual(handler.matchType!, MatchType.perfectMatch(0, 0))

其中(0,0)输入索引,返回值。

有没有可能在不知道具体数字的情况下对枚举进行比较?