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Swift 4-带UIPickerView的自定义UICollectionReusableView

swift ios

user979331 · 技术社区 · 6 年前

我建立了一个习惯 UICollectionReusableView 像这样的班级:

protocol ReviewFooterDelegate: NSObjectProtocol {
    func submitReviewDelegate(text: String, rating: Float)
}

class ReviewFooterCell: UICollectionReusableView {

    @IBOutlet var text: UITextView!
    @IBOutlet var submitButton: UIButton!
    @IBOutlet var rating: CosmosView!
    @IBOutlet var problem: UITextField!
    var reviewFooterDelegate: ReviewFooterDelegate!

    @IBAction func submitButtonPressed(_ sender: Any) {

        reviewFooterDelegate.submitReviewDelegate(text: self.text.text, rating: Float(rating.rating))
    }
}

UITapGestureRecognizer 致 UITextField UIPickerView ,这是我的控制器中使用此自定义类的内容:

viewForSupplementaryElementOfKind 方法:

    let footerView = collectionView.dequeueReusableSupplementaryView(ofKind: kind, withReuseIdentifier: "ReviewsFooter", for: indexPath) as! ReviewFooterCell
    footerView.reviewFooterDelegate = self
    let problemGesture = UITapGestureRecognizer(target: self, action: #selector(problemTapped))
    footerView.problem.addGestureRecognizer(problemGesture)
    return footerView

下面是problemTapped方法:

@objc func problemTapped(sender : UITapGestureRecognizer) {

        pickerView.delegate = self
        pickerView.dataSource = self

        let toolBar = UIToolbar()
        toolBar.barStyle = UIBarStyle.default
        toolBar.isTranslucent = true
        toolBar.sizeToFit()

        let doneButton = UIBarButtonItem(title: "Done", style: UIBarButtonItem.Style.plain, target: self, action: #selector(ProfessionalReviews.donePicker))
        doneButton.tintColor = UIColor(red: 30.0 / 255.0, green: 53.0 / 255.0, blue: 94.0 / 255.0, alpha: 1.0)

        let spaceButton = UIBarButtonItem(barButtonSystemItem: UIBarButtonItem.SystemItem.flexibleSpace, target: nil, action: nil)

        let cancelButton = UIBarButtonItem(title: "Cancel", style: UIBarButtonItem.Style.plain, target: self, action: #selector(ProfessionalReviews.cancelPicker))
        cancelButton.tintColor = UIColor(red: 30.0 / 255.0, green: 53.0 / 255.0, blue: 94.0 / 255.0, alpha: 1.0)

        toolBar.setItems([cancelButton, spaceButton, doneButton], animated: false)
        toolBar.isUserInteractionEnabled = true

        /*
        problem.inputAccessoryView = toolBar
        view.addSubview(problem)
        problem.inputView = pickerView
        problem.becomeFirstResponder()
        */
    }

现在我陷入了下一步该做什么,我该如何设置 输入框 作为第一反应者在我的定制课上?

0 回复 | 直到 6 年前

Zion 6 年前

正如其他人所评论的,您不需要UITapGestureRecognizer就可以完成您的要求:

UITextField以显示UIPickerView。

而是设置textField的 inputView 给你的挑夫。下面是一个代码示例。视图控制器有一个textField,点击时会显示pickerView。此项目在github上;请参阅下面的参考资料。

class ViewController: UIViewController, UIPickerViewDelegate, UIPickerViewDataSource {

    @IBOutlet weak var pickerTextField: UITextField!

    var pickOption = ["one", "two", "three", "four", "five"]

    var pickerView: UIPickerView!

    override func viewDidLoad() {
        super.viewDidLoad()
        let pickerView = UIPickerView()

        // Assign the pickerView delegate
        pickerView.delegate = self

        // Assign the textField's inputView to be the picker
        pickerTextField.inputView = pickerView
    }

    // UIPickerViewDelegate methods
    func numberOfComponents(in pickerView: UIPickerView) -> Int {
        return 1
    }

    func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        return pickOption.count
    }

    func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
        return pickOption[row]
    }

    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
        pickerTextField.text = pickOption[row]
    }
}

由于您的textView包含在UICollectionReusableView中,因此您可以在单元格类中使用一个函数来设置textView的inputView,如下所示:

class ReviewFooterCell: UICollectionReusableView {
    func setTextFieldInputView(pickerView: UIPickerView) {
        problem.inputView = pickerView   
    }    
}

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