是否有针对aws cognito API的JWT验证的java示例?

我只是挣扎着想分享一下。

如果您使用maven,请将此添加到pom中。xml

<dependency>
    <groupId>com.auth0</groupId>
    <artifactId>java-jwt</artifactId>
    <version>3.3.0</version>
</dependency>
<dependency>
    <groupId>com.auth0</groupId>
    <artifactId>jwks-rsa</artifactId>
    <version>0.4.0</version>
</dependency>

如果使用gradle add

compile 'com.auth0:jwks-rsa:0.4.0'
compile 'com.auth0:java-jwt:3.3.0'

创建一个实现RSAKeyProvider的类

import com.auth0.jwk.JwkException;
import com.auth0.jwk.JwkProvider;
import com.auth0.jwk.JwkProviderBuilder;
import com.auth0.jwt.interfaces.RSAKeyProvider;

import java.net.MalformedURLException;
import java.net.URL;
import java.security.interfaces.RSAPrivateKey;
import java.security.interfaces.RSAPublicKey;

public class AwsCognitoRSAKeyProvider implements RSAKeyProvider {

    private final URL aws_kid_store_url;
    private final JwkProvider provider;

    public AwsCognitoRSAKeyProvider(String aws_cognito_region, String aws_user_pools_id) {
        String url = String.format("https://cognito-idp.%s.amazonaws.com/%s/.well-known/jwks.json", aws_cognito_region, aws_user_pools_id);
        try {
            aws_kid_store_url = new URL(url);
        } catch (MalformedURLException e) {
            throw new RuntimeException(String.format("Invalid URL provided, URL=%s", url));
        }
        provider = new JwkProviderBuilder(aws_kid_store_url).build();
    }


    @Override
    public RSAPublicKey getPublicKeyById(String kid) {
        try {
            return (RSAPublicKey) provider.get(kid).getPublicKey();
        } catch (JwkException e) {
            throw new RuntimeException(String.format("Failed to get JWT kid=%s from aws_kid_store_url=%s", kid, aws_kid_store_url));
        }
    }

    @Override
    public RSAPrivateKey getPrivateKey() {
        return null;
    }

    @Override
    public String getPrivateKeyId() {
        return null;
    }
}

现在,您可以通过以下方式验证您的令牌

String aws_cognito_region = "us-east-1"; // Replace this with your aws cognito region
String aws_user_pools_id = "us-east-1_7DEw1nt5r"; // Replace this with your aws user pools id
RSAKeyProvider keyProvider = new AwsCognitoRSAKeyProvider(aws_cognito_region, aws_user_pools_id);
Algorithm algorithm = Algorithm.RSA256(keyProvider);
JWTVerifier jwtVerifier = JWT.require(algorithm)
    //.withAudience("2qm9sgg2kh21masuas88vjc9se") // Validate your apps audience if needed
    .build();

String token = "eyJraWQiOiJjdE.eyJzdWIiOiI5NTMxN2E.VX819z1A1rJij2"; // Replace this with your JWT token
jwtVerifier.verify(token);

请注意,JwkProviderBuilder将构建一个带有LRU缓存的JwkProvider,该缓存可以缓存从aws密钥存储库检索到的密钥,这非常整洁!可以使用生成器更改缓存规则。

[更新] 已将创建JwkProvider移动到构造函数,因此正如@danieln所评论的那样,缓存受到尊重

至于这个秘密,你是指特定于客户端的应用程序吗?这是您在创建和应用程序客户端时得到的。转到AWS控制台和Cognito。选择适当的用户池,单击App Client。这是个秘密,但你必须确保在创建应用程序客户端时选择创建它的选项(或者不使用)。否则,请制作一个新的。

您可以使用标准验证令牌 JWT library . 此外,验证JWT令牌还涉及几个步骤。虽然我找不到Java示例,但下面是一个NodeJS示例,它将解释验证过程。

const jwt = require('jsonwebtoken');
const jwtToken = "sampletoken****";
const jwkPem = { "alg" : "RS256", "kid" : "samplekid****" }

var decodedJwt = jwt.decode(jwtToken, {complete: true});

//Fail if the token is not jwt
if (!decodedJwt) {
    console.log("Not a valid JWT token");
    return;
}

//Fail if token is not from your User Pool
if (decodedJwt.payload.iss != iss) {
    console.log("invalid issuer");
    return;
}

//Reject the jwt if it's not an 'Access Token'
if (!(decodedJwt.payload.token_use == 'id' || 
    decodedJwt.payload.token_use == 'access')) {
    console.log("token_use is invalid");
    return;
}

//Get the kid from the token and retrieve corresponding PEM
var kid = decodedJwt.header.kid;
var pem = jwkPem[kid];
if (!pem) {
    console.log("Invalid access token");
    return;
}

//Verify the signature of the JWT token to ensure it's really coming from your User Pool and that it has not expired
jwt.verify(jwtToken, pem, { issuer: iss, maxAge: 3600000}, function(err, payload) {
  if(err) {
    console.log(err);
  } else {
    console.log("Authorization successful");
  }
});