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PHP用str\u replace将数字转换为字符串而不混淆

str-replace string arrays php

Ali Özen · 技术社区 · 7 年前

1=>A
2=>B
3=>C
4=>D
5=>E
6=>F
7=>G
8=>H
9=>I
10=>J
11=>K
12=>L

function name($string) {
    $find=array("1","2","3","4","5","6","7","8","9","10","11","12");
    $replace=array("A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L");
    $string=str_replace($find,$replace,$string);  
    return $string;
}

name("12"); 它不会回来了 L 它的回归 AB .

实际上这是有道理的。回信。我怎么回去 L 在这个函数中?我该怎么办?提前谢谢。

6 回复 | 直到 7 年前

Mohammad DefenestrationDay 7 年前

str_replace() with array用数组项中的任何匹配项替换提供的字符串。所以使用 array_search() 如下图所示

$result = $replace[array_search($string, $find)];

所以你的代码改成

function name($string) {
    $find = array("1","2","3","4","5","6","7","8","9","10","11","12");
    $replace = array("A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L");  
    return $replace[array_search($string, $find)]; 
}

签入结果 demo

Nigel Ren 7 年前

问题是 str_replace() documentation ...

替换订单明白了

多次替换。另请参见本文档中的示例。

如果你用 strtr()

$string=strtr($string, array_combine($find, $replace));

nice_dev 7 年前

chr

<?php 

function name($string) {
   return chr(intval($string) + 64);
}

更新:

ord('A') A 转换为整数的字符串参数,并从中减去1,以获得我们正在查找的字符的ASCII值。 chr()

function name($string) {
   return chr(intval($string) + ord('A') - 1);
}

Ulrich Eckhardt 7 年前

创建简单映射:

$mapping = [
    '1' => 'A',
    '2' => 'B',
    '12' => 'L',
];
if (!array_key_exists($string, $mapping)) {
    throw new Exception('invalid input provided');
}
return $mapping[$string];

A l w a y s S u n n y 7 年前

range() 而不是长时间 键=>价值 数组。我认为你现在的要求 str_repalce() 范围() 会变魔术:)

<?php
  function name($num){
    $array = range('A','Z');
    $array = array_filter(array_merge(array(0), $array));
    return $array[$num];
  }

 echo name(12);

演示: https://3v4l.org/kl9jn

Paolo 7 年前

str_replace chr

function name($string) {
    return chr( $string + 64 );
}

请注意,这将是一个长单词 $string 实际上包含一个范围为1的数字。。26

但如果-出于某种原因-你想坚持 str\u替换

function name($string) {
    $string = " " . $string . " ";
    $find=array(" 1 "," 2 "," 3 "," 4 "," 5 "," 6 "," 7 "," 8 "," 9 "," 10 "," 11 "," 12 ");
    $replace=array("A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L");
    $string=str_replace($find,$replace,$string);  
    return $string;
}