我目前正在使用java解决一个假设的生产者-消费者问题。目标是拥有一个1000字节的操作系统,但只有500字节可用于线程,因为驱动程序和其他操作已经消耗了500字节。螺纹如下:
-
启动10秒BubbleWitch2会话的线程,每个会话需要100字节的RAM
第二
-
启动Spotify流的线程为20秒,每秒需要250字节的RAM
您还应考虑操作系统同时支持系统这一事实
活动并管理其上安装的设备的处理器、内存和磁盘空间。
因此,额外创建:
-
系统和管理线程,它们一起需要每秒50字节的RAM,以及
一旦调用,执行一段随机时间。
-
一个线程,用于安装2 KB的新安全更新,该更新将存储到磁盘,需要150
安装时每秒RAM字节数。假设系统中有足够的磁盘容量来支持
此线程。
操作系统的容量仅为每秒200字节,因此像spotify这样的大型线程将遇到延迟或被迫等待。我使用了代码,据我所知,这些代码实现了这一点。我还需要生成退出时间,这是我用时间戳完成的,并计算线程的平均等待时间。
我已经在我的解决方案中包含了system.out.print的平均等待时间的代码,但无论我做什么,它实际上都没有输出时间,就像它们不存在一样。
我也不确定缓冲区大小限制是否有效,因为这是一个毫秒的问题。有没有办法从下面的代码中判断这是否有效?
我的主要方法。
public class ProducerConsumerTest {
public static void main(String[] args) throws InterruptedException {
Buffer c = new Buffer();
BubbleWitch2 p1 = new BubbleWitch2(c,1);
Processor c1 = new Processor(c, 1);
Spotify p2 = new Spotify(c, 2);
SystemManagement p3 = new SystemManagement(c, 3);
SecurityUpdate p4 = new SecurityUpdate(c, 4, p1, p2, p3);
p1.setName("BubbleWitch2 ");
p2.setName("Spotify ");
p3.setName("System Management ");
p4.setName("Security Update ");
p1.setPriority(10);
p2.setPriority(10);
p3.setPriority(10);
p4.setPriority(5);
c1.start();
p1.start();
p2.start();
p3.start();
p4.start();
p2.join();
p3.join();
p4.join();
System.exit(0);
}
}
My buffer class
import java.text.DateFormat;
import java.text.SimpleDateFormat;
/**
* Created by Rory on 10/08/2014.
*/
class Buffer {
private int contents, count = 0, process = 0;
private boolean available = false;
private long start, end, wait, request= 0;
private DateFormat time = new SimpleDateFormat("mm:ss:SSS");
public synchronized int get() {
while (process <= 500) {
try {
wait();
} catch (InterruptedException e) {
}
}
process -= 200;
System.out.println("CPU After Process " + process);
notifyAll();
return contents;
}
public synchronized void put(int value) {
while (process >= 1000) {
start = System.currentTimeMillis();
try {
wait();
} catch (InterruptedException e) {
}
end = System.currentTimeMillis();
wait = end - start;
count++;
request += wait;
System.out.println("Application Request Wait Time: " + time.format(wait));
process += value;
contents = value;
notifyAll();
}
}
}
我的安全更新类
import java.lang.*;
import java.lang.System;
/**
* Created by Rory on 11/08/2014.
*/
class SecurityUpdate extends Thread {
private Buffer buffer;
private int number;
private int bytes = 150;
private int process = 0;
public SecurityUpdate(Buffer c, int number, BubbleWitch2 bubbleWitch2, Spotify spotify, SystemManagement systemManagement) throws InterruptedException {
buffer = c;
this.number = number;
bubbleWitch2.join();
spotify.join();
systemManagement.join();
}
public void run() {
for (int i = 0; i < 15; i++) {
buffer.put(i);
System.out.println(getName() + this.number
+ " put: " + i);
try {
sleep(1500);
} catch (InterruptedException e) {
}
}
System.out.println("-----------------------------");
System.out.println("Security Update has finished executing.");
System.out.println("------------------------------");
}
}
我的处理器类
class Processor extends Thread {
private Buffer processor;
private int number;
public Processor(Buffer c, int number) {
processor = c;
this.number = number;
}
public void run() {
int value = 0;
for (int i = 0; i < 60; i++) {
value = processor.get();
System.out.println("Processor #"
+ this.number
+ " got: " + value);
}
}
}
我的泡泡球课
import java.lang.*;
import java.lang.System;
import java.sql.Timestamp;
/**
* Created by Rory on 10/08/2014.
*/
class BubbleWitch2 extends Thread {
private Buffer buffer;
private int number;
private int bytes = 100;
private int duration;
public BubbleWitch2(Buffer c, int pduration) {
buffer = c;
duration = pduration;
}
long startTime = System.currentTimeMillis();
public void run() {
for (int i = 0; i < 10; i++) {
buffer.put(bytes);
System.out.println(getName() + this.number
+ " put: " + i);
try {
sleep(1000);
} catch (InterruptedException e) {
}
}
long endTime = System.currentTimeMillis();
long timeTaken = endTime - startTime;
java.util.Date date = new java.util.Date();
System.out.println("-----------------------------");
System.out.println("BubbleWitch2 has finished executing.");
System.out.println("Time taken to execute was " +timeTaken+ " milliseconds");
System.out.println("Time Bubblewitch2 thread exited Processor was " + new Timestamp(date.getTime()));
System.out.println("-----------------------------");
}
}
我的系统管理
class SystemManagement extends Thread {
private Buffer buffer;
private int number, min = 1, max = 15;
private int loopCount = (int) (Math.random() * (max - min));
private int bytes = 50;
private int process = 0;
public SystemManagement(Buffer c, int number) {
buffer = c;
this.number = number;
}
public void run() {
for (int i = 0; i < loopCount; i++) {
buffer.put(50);
System.out.println(getName() + this.number
+ " put: " + i);
try {
sleep(1000);
} catch (InterruptedException e) {
}
}
System.out.println("-----------------------------");
System.out.println("System Management has finished executing.");
System.out.println("-----------------------------");
}
}
我的spotify类
导入java.sql.Timestamp;
/**
* Created by Rory on 11/08/2014.
*/
class Spotify extends Thread {
private Buffer buffer;
private int number;
private int bytes = 250;
public Spotify(Buffer c, int number) {
buffer = c;
this.number = number;
}
long startTime = System.currentTimeMillis();
public void run() {
for (int i = 0; i < 20; i++) {
buffer.put(bytes);
System.out.println(getName() + this.number
+ " put: " + i);
try {
sleep(1000);
} catch (InterruptedException e) {
}
}
long endTime = System.currentTimeMillis();
long timeTaken = endTime - startTime;
java.util.Date date = new java.util.Date();
System.out.println(new Timestamp(date.getTime()));
System.out.println("-----------------------------");
System.out.println("Spotify has finished executing.");
System.out.println("Time taken to execute was " + timeTaken + " milliseconds");
System.out.println("Time that Spotify thread exited Processor was " + date);
System.out.println("-----------------------------");
}
}
我可能还需要给一两节课添加时间戳,但有人知道如何让我的平均时间真正打印出来吗?或者是什么阻止了它,如果缓冲区限制在这里有效地显示出来(假设我们谈论的是毫秒?)
谢谢