a的每个级别的颜色
sunburst
打印自
plot_ly
library(plotly)
p <- plot_ly(labels = c("Eve", "Cain", "Seth", "Enos", "Noam", "Abel", "Awan", "Enoch", "Azura"),
parents = c("", "Eve", "Eve", "Seth", "Seth", "Eve", "Eve", "Awan", "Eve"),
values = c(65, 14, 12, 10, 2, 6, 6, 4, 4),
type = 'sunburst',
branchvalues = 'total')
layout(p, colorway = c("#EE5859", "#EE5859", "#D2CBB8", "#585859", "#AAAAAA"))
但是,我正在尝试创建在每个级别上具有相同颜色的分支。由于上述行为,我只能相信,如果他们有相同数量的孩子,像下面这样。
layout(p, colorway = c("#585859", "#EE5859", "#D2CBB8", "#EE5859", "#AAAAAA"))
那么,有没有一种方法可以确定每个级别的太阳辐射的透明度是相同的,并且独立于分支中的级别?在这种情况下,2级为100%,3级为50%?