在groovy中展开操作符?

你在找地图接线员。

def foo(map, name) {
  println(map)
}

foo("bar", hi: "bye")

def otherMap = [hi: "world"]
foo("bar", hi: "bye", *:otherMap)
foo("bar", *:otherMap, hi: "bye")

印刷品:

["hi":"bye"]
["hi":"world"]
["hi":"bye"]

我不确定你到底想要达到什么目标,所以这里有几个可能性:

如果要将第二个映射的内容添加到第一个映射,则 leftShift 接线员是前进的道路:

def foo(name, map) {
  println(map)
}

def otherMap = [hi: "world"]
foo("bar", [hi: "bye"] << otherMap)

如果要通过参数的名称访问参数,请使用映射:

def foo(Map args) {
  println args.map
}

def otherMap = [hi: "world"]
foo(name:"bar", first:[hi: "bye"], map:otherMap)

如果要全部或仅打印最后一个参数,请使用varargs:

def printLast(Object[] args) {
  println args[-1]
}

def printAll(Object[] args) {
  args.each { println it }
}

def printAllButName(name, Map[] maps) {
  maps.each { println it }
}

def otherMap = [hi: "world"]
printLast("bar", [hi: "bye"], otherMap)
printAll("bar", [hi: "bye"], otherMap)
printAllButName("bar", [hi: "bye"], otherMap)